Python Coding Examples for Beginners

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Explore various Python coding examples including calculating Fibonacci numbers, manipulating arrays, implementing Euclid's algorithm, finding prime numbers, and solving list difference problems. The examples cover a range of fundamental Python concepts and are accompanied by explanations to help beginners understand and practice coding in Python effectively.


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  1. BAZI RNEK PYTHON KODLARI

  2. split from index k and add first part of arr to the end # Calculates the first n Fibonacci numbers n = 100 # Keep track of the two most recent Fibonacci numbers a, b = 1, 1 print(a, b, end='') for i in range(2, n+1): # The next number (b) is a+b, and a becomes the previous b a, b = b, a+b print(' ', b, end='') def splitArr(arr, n, k): for i in range(n-1, k-1, -1): x = arr[n-1] for j in range(n-1, 0, -1): arr[j] = arr[j - 1] arr[0] = x # main arr = [12, 10, 5, 6, 52, 36] n = len(arr) position = 2 splitArr(arr, n, position) for i in range(0, n): print(arr[i], end = ' ')

  3. Euclid's algorithm for finding the gcd of a number >>> a, b = 1071, 462 >>> while b: ... a, b = b, a % b >>> print(a) def SieveOfEratosthenes(n): # Create a boolean array "prime[0..n]" and initialize all entries it as true. A value in prime[i] will finally be false if i is Not a prime, else true. prime = [True for i in range(n+1)] p = 2 while (p * p <= n): # If prime[p] is not changed, then it is a prime if (prime[p] == True): # Update all multiples of p for i in range(p * 2, n+1, p): prime[i] = False p += 1 # Print all prime numbers for p in range(2, n): if prime[p]: print(p) print(SieveOfEratosthenes(50))

  4. SAMPLE EXAM QUESTONS A a daki python fonksiyonu iki listeyi arg man olarak al p aralar ndaki farkl elemanlar n listesini geri d nd recektir. Eksik kalan sat r yaz n z. def Diff(li1, li2): li_dif=[] for i in li1+li2: A a daki python kodu ekrana ne basar? def func(li, n): li2=[] for i in range(len(li)): if(li[i]==n): li2.append(i) return li2 test_list = [1, 3, 4, 3, 6, 7, 9, 3, 2, 5] print ("Result is : " + str(func(test_list, 3))) if i not in li1 or i not in li2: li_dif.append(i) return li_dif Result is : [1, 3, 7] basar.

  5. def spam() : eggs = 'spam' print(eggs) flip_flop = True increment = 0 number = 6 while number > 1 : if flip_flop == True : increment = 2 flip_flop = False else : increment = -3 flip_flop = True number = number + increment print(number) def bacon() : eggs = 'bacon' print(eggs) spam() print(eggs) eggs = 'global' bacon() print(eggs)

  6. def spam(number) : if (number[0] % 2) == 0 : number[0] = number[0] // 4 print(number[0]) def spam(number) : if (number % 2) == 0 : number = number // 4 print(number) def bacon(number) : if (number[0] % 2) != 0 : number[0] = 5 * number[0] + 1 print(number[0]) def bacon(number) : if (number % 2) != 0 : number = 5 * number + 1 print(number) number = [30] while number[0] > 1 : bacon(number) spam(number) number = 30 while number > 1 : bacon(number) spam(number)

  7. def isPalindrome(s): return s == s[::-1] # Driver code s = "malayalam" ans = isPalindrome(s) if ans: print("Yes") else: print("No")

  8. >>> scores = [87, 75, 75, 50, 32, 32] >>> ranks = [] >>> for score in scores: ... ranks.append(scores.index(score) + 1) ... >>> ranks [1, 2, 2, 4, 5, 5]

  9. def removeDuplicate(str): s=set(str) s="".join(s) print("Without Order:",s) t="" for i in str: if(i in t): pass else: t=t+i print("With Order:",t) str="geeksforgeeks" removeDuplicate(str)

  10. def uncommon(A, B): un_comm = [i for i in B.split() if i not in A.split()] return un_comm #Driver code A = "Geeks for Geeks" B = "Learning from Geeks for Geeks" print(uncommon(A, B))

  11. # initializing string test_str = 'Geeksforgeeks is best for geeks and CS' # printing original string print("The original string is : " + str(test_str)) # initializing word list word_list = ["best", 'CS', 'for'] # initializing replace word repl_wrd = 'gfg' # Replace multiple words with K # Using join() + split() + list comprehension res = ' '.join([repl_wrd if idx in word_list else idx for idx in test_str.split()]) # printing result print("String after multiple replace : " + str(res))

  12. def checkEmpty(input, pattern): # If both are empty if len(input)== 0 and len(pattern)== 0: return 'true' # If only pattern is empty if len(pattern)== 0: return 'true' while (len(input) != 0): # find sub-string in main string index = input.find(pattern) # check if sub-string founded or not if (index ==(-1)): return 'false' # slice input string in two parts and concatenate input = input[0:index] + input[index + len(pattern):] return 'true' input ='GEEGEEKSKS' pattern ='GEEKS' print (checkEmpty(input, pattern))

  13. # To find minimum sum of product of number def findMinSum(num): sum = 0 # Find factors of number and add to the sum i = 2 while(i * i <= num): while(num % i == 0): sum += i num /= i i += 1 sum += num # Return sum of numbers having minimum product return sum # Driver Code num = 12 print findMinSum(num)

  14. def hailstone(n): count = 1 """Print the terms of the 'hailstone sequence' from n to 1.""" assert n > 0 print(n) if n > 1: if n % 2 == 0: count += hailstone(n / 2) else: count += hailstone((n * 3) + 1) return count result = hailstone(10) print(result)

  15. #Function to get gcd of a and b def gcd(a, b): if b == 0: return a; else: return gcd(b, a%b) # Driver program to test above functions arr = [1, 2, 3, 4, 5, 6] leftRotate(arr, 2, 6) print(arr, end=" ") #Function to left rotate arr[] of size n by d def leftRotate(arr, d, n): for i in range(gcd(d,n)): # move i-th values of blocks temp = arr[i] j = i while 1: k = j + d if k >= n: k = k - n if k == i: break arr[j] = arr[k] j = k arr[j] = temp

  16. # Function to do insertion sort def insertionSort(arr): # Traverse through 1 to len(arr) for i in range(1, len(arr)): key = arr[i] # Move elements of arr[0..i-1], that are greater than key, to one position ahead of their current position j = i-1 while j >= 0 and key < arr[j] : arr[j + 1] = arr[j] j -= 1 arr[j + 1] = key # Driver code to test above arr = [12, 11, 13, 5, 6] insertionSort(arr) for i in range(len(arr)): print ("% d" % arr[i])

  17. # Program to get list of specified number of consecutive elements def grouping(nums): list=[] count=1 for i in range(1, len(nums)): if nums[i] != nums[i-1]: list.append((nums[i-1], count)) count=1 else: count+=1 return list def get_list(nums, n): result = [a[0] for a in grouping(nums) if a[1] == n] return result nums1 = [1, 1, 3, 4, 4, 5, 6, 5, 6, 7] n = 2 print(get_list(nums1, n))

  18. #function to find the difference between consecutive numbers in a given list def diff_consecutive_nums(nums): result = [b-a for a, b in zip(nums[:-1], nums[1:])] return result #function to reverse each list in a given list of lists def reverse_list_lists(nums): nums=[i[::-1] for i in nums] return nums nums = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]] print(reverse_list_lists(nums)) #program to create a list whose ithelement is the maximum of the first i elements from a input list def test(nums): return [max(nums[:i]) for i in range(1, len(nums) + 1)] nums = [0, -1, 3, 8, 5, 9, 8, 14, 2, 4, 3, -10, 10, 17, 41, 22, -4, -4, -15, 0] print(test(nums))

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