ENZYME KINETICS

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BIOCHEMISTY
 
BINITA RANI
ASSOCIATE PROFESSOR (DAIRY CHEMISTRY)
FACULTY OF DAIRY TECHNOLOGY
S.G.I.D.T., BVC CAMPUS,
P.O.- BVC, DIST.-PATNA-800014
 
Course No.-DTC-111,    Credit Hours – 2 (1+1)
 
          
ENZYME KINETICS
 
 
In the 
absence of enzyme =>
 conversion of S to P is 
slow
 and
uncontrolled
.
 
In presence of a 
specific enzyme =>
 S is converted 
swiftly and
specifically
 to 
product
.
 
Enzyme is 
specific
 
=>
 it will not convert A to B or X to Y.
 
Enzymes also provide 
=>
 
rate acceleration
.
On comparing rate of a 
chemical reaction in solution =>
 with =>
rate of the same reaction with the 
reactants bound to enzyme
=>
 
enzyme reaction 
will occur up to 
1014 times faster
.
 
A unit is 
=>
 amount of enzyme 
=>
 that will catalyze the
conversion of 
1 μ mol of substrate 
to
 
product
 
in 
1 min
under a given set of conditions.
 
Units of enzyme can be converted to 
=>
 milligrams of
enzyme by a 
conversion factor 
called 
=>
 
specific activity
.
Specific activity 
is 
=>
 amount of enzyme activity per
milligram of protein (micromoles of product formed / minute
/ milligram of protein, or units per milligram).
 
For a pure enzyme 
=>
 under a defined set of conditions 
=>
the 
specific activity 
is a 
constant
; however, different enzymes
have 
=>
 
different specific activities
.
 
An 
enzyme assay 
is 
=>
 
act of measuring 
how 
fast
 a given
(or unknown) amount of enzyme will convert substrate to
product - 
act of measuring a velocity
.
 
Velocity
 (rate, v, activity, d[P]/dt, d[S]/dt) is 
=>
 how fast an
enzyme converts 
substrate to product
 
=>
 the amount of
substrate consumed, or product formed 
per unit time
.
Units are 
micromoles per minute 
(μmol/min) units.
 
     
The Michaelis-Menten Equation
primary function of enzymes =>
 to 
enhance rates 
of reactions
=>
 so that they are compatible with 
=>
 needs of the organism.
To understand how enzymes function 
=>
 we need a
     kinetic description of their activity.
For many enzymes 
=>
 the rate of catalysis 
V0
 
=>
 which is
defined as 
number of moles of product formed per second
=>
 varies with 
substrate concentration 
[S].
The rate of catalysis 
=>
 
rises linearly as substrate
concentration increases 
and 
=>
 then 
begins to level off 
and
approach a maximum at 
higher substrate concentrations
.
 
Effect of substrate concentration on the initial velocity of an enzyme-catalyzed reaction
 
 
The extent of 
product formation 
is determined 
=>
 as a
function of time => 
for a 
series of substrate concentrations
.
In each case 
=>
 amount of 
product formed 
increases with time
=>
 although eventually 
=>
 a time is reached when 
=>
 
there is
no net change in the concentration
 
of S or P.
Enzyme is still actively converting 
=>
 
substrate into product
and visa versa 
=>
 but 
reaction equilibrium 
has been attained.
We define 
V0
 as 
=>
 
rate
 
of increase in product with time 
when
[P] is low 
=>
 that is 
=>
 at times close to 
zero
 (hence, V0).
Thus, 
V0
 is determined for each substrate concentration
 => 
by
measuring the 
rate of product formation at early times 
before
P accumulates .
 
We begin our 
kinetic examination 
of 
enzyme activity 
with
the graph shown in Figure.
At a 
fixed concentration 
of enzyme
 
=>
 V 0 is almost
linearly proportional 
to [S] when [S] is 
small
 but
is nearly 
independent
 of [S] when [S] is 
large
.
In 1913, Leonor Michaelis and Maud Menten proposed 
=>
a simple model to 
=>
 account for these kinetic
characteristics.
The 
critical feature 
in their treatment is 
=>
 that a specific
ES complex 
is a necessary intermediate in catalysis.
The model proposed 
=>
 is the simplest one that accounts
for the kinetic properties of many enzymes.
 
To simplify matters 
=>
 we will work under 
steady-state
assumption.
 
 In a steady state 
=>
 the concentrations of intermediates, in
this case 
[ES] =>
 
stay the same 
even if 
=>
 concentrations of
starting materials and products are changing.
 
This occurs 
=>
 when the rates of formation and breakdown of
the 
ES complex 
are 
equal
.
Setting the right-hand sides of equations 3 and 4 equal gives
 
Now let us examine the numerator of equation 8.
The concentration of uncombined substrate [S] is very
nearly 
=>
 equal to the total substrate concentration 
=>
provided that the concentration of enzyme is much lower
than that of substrate.
 
The concentration of 
uncombined enzyme 
[E] is equal to
the 
total enzyme concentration 
[E]T minus the
concentration of the 
ES complex.
 
At very 
low substrate concentration =>
 when [S] is much less
than K M, V0 = (V max/K M)[S] 
=>
 that is 
=>
 
the rate is
directly  proportional to the substrate concentration
.
At 
high substrate concentration =>
 when [S] is much greater
than K M, V0 = V max 
=>
 that is 
=>
 the 
rate is maximal =>
independent of substrate concentration
.
The meaning of K M is evident from equation 15.
When V0 = V max/2
Then [S] = KM
Thus, 
K M 
is equal to the substrate concentration at which 
=>
the 
reaction rate is half its maximal value
.
Km
 is an 
important characteristic 
of an 
enzyme-catalyzed
reaction
 and is significant for 
=>
 
its biological function
.
For most enzymes, 
Km
lies between 
10-1 and 10-7 M
.
 
     
The Significance of Km and Vmax Values
Km
 value for an enzyme depends on 
=>
 
particular substrate 
and on
environmental conditions => pH, temperature, and ionic strength.
Km
 is 
=> concentration of substrate 
at which half the active sites are
filled. Thus 
=>
 Km provides a measure of the substrate concentration
required for 
=>
 
significant catalysis 
to occur.
Km
 is equal to 
=> dissociation constant of ES complex 
if k2 is 
< 
k-1 .
High Km indicates 
=>
 
weak
 binding 
=>
 a 
low Km 
indicates 
strong
binding
. Km indicates 
affinity of ES complex 
only when k- 1 is 
>
 k2.
The maximal rate 
=>
 
V max =>
 reveals the turnover number of an
enzyme 
=>
 i.e. the number of substrate molecules converted into
product by an enzyme molecule in a unit time 
=>
 when enzyme is
fully saturated with substrate.
 
The Double-Reciprocal Plot
Michaelis-Menten equation 
can be algebraically transformed into
equations that are more useful in 
plotting experimental data
 
 
This
 
form of Michaelis-Menten equation 
is called 
=>
Lineweaver-Burk equation
.
For enzymes obeying the Michaelis-Menten relationship 
=>
 a
plot of 
1/V0 
versus 
1/[S] 
yields  
=>
 a straight line.
This line has a slope of 
Km/Vmax =>
 an intercept of 
1/Vmax 
on
the 
1/V0 
axis, and 
=>
 an intercept of -1/Km on the 1/[S] axis.
 
The Double-
Reciprocal
 Plot
 
The double-reciprocal presentation 
=>
 also called a
Lineweaver-Burk plot 
=>
 has the great advantage of
allowing a 
more accurate determination of => Vmax
, which
can only be approximated from 
=>
 a simple plot of 
V0
versus [S].
Double-reciprocal plot 
of enzyme reaction rates is very
useful in 
=>
 distinguishing between certain types of
enzymatic reaction 
mechanisms
 and 
=>
 in analyzing 
enzyme
inhibition
.
 
THANKS
Slide Note
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In enzyme kinetics, the presence of specific enzymes accelerates reactions, with substrate conversion catalyzed swiftly and specifically. Enzyme units and specific activity play critical roles, impacting reaction rates and product formation. The Michaelis-Menten Equation explains enzyme behavior, with catalysis rates varying with substrate concentration. Explore the impact of substrate concentration on reaction velocity and the time-dependent product formation.

  • Enzyme Kinetics
  • Michaelis-Menten
  • Enzyme Assay
  • Reaction Rates
  • Substrate Concentration

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  1. BIOCHEMISTY Course No.-DTC-111, Credit Hours 2 (1+1) ENZYME KINETICS BINITA RANI ASSOCIATE PROFESSOR (DAIRY CHEMISTRY) FACULTY OF DAIRY TECHNOLOGY S.G.I.D.T., BVC CAMPUS, P.O.- BVC, DIST.-PATNA-800014

  2. In the absence of enzyme => conversion of S to P is slow and uncontrolled. In presence of a specific enzyme => S is converted swiftly and specifically to product. Enzyme is specific => it will not convert A to B or X to Y. Enzymes also provide => rate acceleration. On comparing rate of a chemical reaction in solution => with => rate of the same reaction with the reactants bound to enzyme =>enzyme reaction will occur up to 1014 times faster.

  3. A unit is => amount of enzyme => that will catalyze the conversion of 1 mol of substrate to product in 1 min under a given set of conditions. Units of enzyme can be converted to => milligrams of enzyme by a conversion factor called => specific activity. Specific activity is => amount of enzyme activity per milligram of protein (micromoles of product formed / minute / milligram of protein, or units per milligram).

  4. For a pure enzyme => under a defined set of conditions => the specific activity is a constant; however, different enzymes have => different specific activities. An enzyme assay is => act of measuring how fast a given (or unknown) amount of enzyme will convert substrate to product - act of measuring a velocity. Velocity (rate, v, activity, d[P]/dt, d[S]/dt) is => how fast an enzyme converts substrate to product => the amount of substrate consumed, or product formed per unit time. Units are micromoles per minute ( mol/min) units.

  5. The Michaelis-Menten Equation primary function of enzymes => to enhance rates of reactions => so that they are compatible with => needs of the organism. To understand how enzymes function => we need a kinetic description of their activity. For many enzymes => the rate of catalysis V0 => which is defined as number of moles of product formed per second => varies with substrate concentration [S]. The rate of catalysis => rises linearly as substrate concentration increases and => then begins to level off and approach a maximum at higher substrate concentrations.

  6. Effect of substrate concentration on the initial velocity of an enzyme-catalyzed reaction

  7. The extent of product formation is determined => as a function of time => for a series of substrate concentrations. In each case => amount of product formed increases with time => although eventually => a time is reached when => there is no net change in the concentration of S or P. Enzyme is still actively converting => substrate into product and visa versa => but reaction equilibrium has been attained. We define V0 as => rate of increase in product with time when [P] is low => that is => at times close to zero (hence, V0). Thus, V0 is determined for each substrate concentration => by measuring the rate of product formation at early times before P accumulates .

  8. We begin our kinetic examination of enzyme activity with the graph shown in Figure. At a fixed concentration of enzyme => V 0 is almost linearly proportional to [S] when [S] is small but is nearly independent of [S] when [S] is large. In 1913, Leonor Michaelis and Maud Menten proposed => a simple model to => account for these kinetic characteristics. The critical feature in their treatment is => that a specific ES complex is a necessary intermediate in catalysis. The model proposed => is the simplest one that accounts for the kinetic properties of many enzymes.

  9. To simplify matters => we will work under steady-state assumption. In a steady state => the concentrations of intermediates, in this case [ES] => stay the same even if => concentrations of starting materials and products are changing. This occurs => when the rates of formation and breakdown of the ES complex are equal. Setting the right-hand sides of equations 3 and 4 equal gives

  10. Now let us examine the numerator of equation 8. The concentration of uncombined substrate [S] is very nearly => equal to the total substrate concentration => provided that the concentration of enzyme is much lower than that of substrate. The concentration of uncombined enzyme [E] is equal to the total enzyme concentration [E]T minus the concentration of the ES complex.

  11. At very low substrate concentration => when [S] is much less than K M, V0 = (V max/K M)[S] => that is => the rate is directly proportional to the substrate concentration. At high substrate concentration => when [S] is much greater than K M, V0 = V max => that is => the rate is maximal => independent of substrate concentration. The meaning of K M is evident from equation 15. When V0 = V max/2 Then [S] = KM Thus, K M is equal to the substrate concentration at which => the reaction rate is half its maximal value. Km is an important characteristic of an enzyme-catalyzed reaction and is significant for => its biological function. For most enzymes, Kmlies between 10-1 and 10-7 M.

  12. The Significance of Km and Vmax Values Km value for an enzyme depends on => particular substrate and on environmental conditions => pH, temperature, and ionic strength. Km is => concentration of substrate at which half the active sites are filled. Thus => Km provides a measure of the substrate concentration required for => significant catalysis to occur. Km is equal to => dissociation constant of ES complex if k2 is < k-1 . High Km indicates => weak binding => a low Km indicates strong binding. Km indicates affinity of ES complex only when k- 1 is > k2. The maximal rate => V max => reveals the turnover number of an enzyme => i.e. the number of substrate molecules converted into product by an enzyme molecule in a unit time => when enzyme is fully saturated with substrate.

  13. The Double-Reciprocal Plot Michaelis-Menten equation can be algebraically transformed into equations that are more useful in plotting experimental data

  14. This form of Michaelis-Menten equation is called => Lineweaver-Burk equation. For enzymes obeying the Michaelis-Menten relationship => a plot of 1/V0 versus 1/[S] yields => a straight line. This line has a slope of Km/Vmax => an intercept of 1/Vmax on the 1/V0 axis, and => an intercept of -1/Km on the 1/[S] axis. The Double- Reciprocal Plot

  15. The double-reciprocal presentation => also called a Lineweaver-Burk plot => has the great advantage of allowing a more accurate determination of => Vmax, which can only be approximated from => a simple plot of V0 versus [S]. Double-reciprocal plot of enzyme reaction rates is very useful in => distinguishing between certain types of enzymatic reaction mechanisms and => in analyzing enzyme inhibition.

  16. THANKS

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