Understanding Slider Crank Mechanism: Practice Problems and Solutions

Explore a practice problem based on a slider crank mechanism, involving calculations for velocity of the slider, velocity of a point on the connecting rod, and angular velocity. Detailed steps and solutions provided to understand the concepts clearly.

• Mechanism
• Practice Problems
• Slider Crank
• Velocity
• Angular Velocity

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Uploaded on Jul 14, 2024 | 1 Views

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1. Practice problem-1 based on today class.

2. Practice problem -1: In a slider crank mechanism, the crank is 480 mm long and rotates at 20 rad/s in the counter-clockwise direction. The length of the connecting rod is 1.6 m. When the Crank turns 600 from the inner-dead centre, determine the (i) Velocity of the slider (answer : 9.7 m/s) (ii) Velocity of a point E located at a distance 450 mm on the connecting rod extended (answer : 10.2 m/s) (iii) Angular velocity of the connecting rod (answer: 3.28 rad/s clockwise)

3. A 1.6 m 104.940 20 rad/s 600 15.060 o B OA = 480 mm In OAB, AB = 1.6 m Velocity of point A Magnitude VA = OA x OA = 0.48 x 20 = 9.60 m/s Direction Velocity of A is perpendicular to OA Angle B = 15.06 degree Angle A = 180 60 15.06 = 104.94 degree

4. VA 14.940 A 1.6 m 75.060 104.940 15.060 600 o VB B Velocity component of A along AB = VA Cos ( 14.940 ) Velocity component of B along AB = VB Cos ( 15.060 ) Velocity component of A along AB = Velocity component of B along AB VA Cos ( 14.940 ) = VB Cos ( 15.060 ) VB = 9.6 x Cos ( 14.940 ) / Cos ( 15.060 ) = 9.605 m/s

5. DIRECTION PERPENDICULAR TO AB VA 14.940 A 1.6 m 75.060 104.940 15.060 600 o VB B Velocity component of A perpendicular to AB = VA Sin ( 14.940) = 9.6 x Sin ( 14.940) DIRECTION PERPENDICULAR TO AB Velocity component of B perpendicular to AB = VB Sin ( 15.060) = 9.605 x Sin ( 15.060) Angular velocity of Link AB = (VA Sin ( 14.940) + VB Sin ( 15.060) ) / AB = 3.11 rad/s

6. Velocity of E along AB , Vex = Velocity of A along AB = Velocity of B along AB. m/s Velocity of A along AB ,VEx = = VA Cos ( 14.940 ) = 9.28 m/s VA sin ( 14.940 ) =2.47 m/s VB sin ( 15.060 ) =2.50 m/s VEy VAy = 2.47 m/s 1.6 m 0.45 m B E A Vby = 2.5 m/s m/s m/s