Trigonometric Identities for Double Angles

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Trigonometric identities
LO: To find the Pythagorean identity and trigonometric
identities for the sine and cosine of the double
angle.
To use those identities to solve problems.
28 September 2024
 
 
y
 
x
 
0
Pythagorean identity
 
From the unit circle we found that:
In this section we are going to look at special kinds of
equations called identities
 
B
 
1
 
OC
 = 
cos
 
 
Since it is a right angled triangle we can
use Pythagoras theorem and say that
 
A
 
C
 
cos
 
 
sin
 
 
BC
 = 
sin
 
 
cos
 
 = 
x
 
sin
 
 = 
y
 
(cos
 

sin
 
)
 
(cos
 

sin
 

)
2
 = 
1
 
cos

 

sin

 

 = 
1
 
cos
 
 
sin
 
 
tan
 

=
 
We can also say that
 
This called The 
Pythagorean identity
 
Another identity
 
 
y
x
O
Double angle identity for cosine
In the following diagram, we draw the reflection of the
angle 
 in the fourth quadrant.
 
The length AC
 
The length AB can be found using the
cosine rule in the 
AOB.
A
1
1
 
We can see that the angle AOB = 2
C
 
Now we have two expressions for AB
 
B
 
So, AB = AC + BC = 2
sin
 
 
AB
2
 = AO
2
 + BO
2
 – 2(AO)(BO)cos
 
(
2
 
AB
2
 = 1
2
 + 1
2
 – 2(1)(1)
cos
 
(
2
 
2
sin
 
 
Squaring both sides
 
4
sin
2
 
 
= 2 - 2
cos
 
(
2
 
Rearranging
 
2
cos
 
(
2
= 2 - 4
sin
2
 
 
Dividing by 2
 
cos
 
(
2
= 1 - 2
sin
2
 
 
sin
 
 
= BC
 
= 
sin
 
 
sin
 
 
This is one identity for the cosine of the double angle
 
 
 
We will use the Pythagorean identity
We are going to use this identity to find more identities
for the cosine of the double angle
 
Rearranging the identity 
 
cos
 
(
2
= 1 - 2
sin
2
 
 
cos

 

sin

 

 = 
1
 
sin

 

 = 
1 – cos

 
 
Substituting in the identity 
 
cos
 
(
2
= 1 – 2
(
1 – cos

 
)
 
cos
 
(
2
= 1 
 2
 + 
2
cos

 
 
cos
 
(
2
= 2
cos

 

 1
 
Expanding brackets
 
Simplifying and rearranging
Double angle identity for cosine
 
 
 
This is another identity for the cosine of the double angle
 
 
 
We will use the Pythagorean identity
We are going to use this last identity to find more
identities for the cosine of the double angle
 
We can substitute the identity 
 
into the identity 
 
cos

 

sin

 

 = 
1
 
cos
 
(
2
= 2
cos

 

 
(
cos

 

sin

 

)
 
Expanding brackets
 
cos
 
(
2
= 2
cos

 

 
cos

 

sin

 
 
cos
 
(
2
= 2
cos

 

 1
 
Simplifying
 
cos
 
(
2
= 
cos

 

– sin

 
Double angle identity for cosine
 
 
 
This is another identity for the cosine of the double angle
 
 
 
Now we are going to find a double-angle identity for sine
 
We can say
 
Equating these equations
 
Factorising
Double angle identity for sine
 
cos
 
(
2
= 1 - 2
sin
2
 
 
We will use the Pythagorean identity
 
cos

 

sin

 

 = 
1
 
cos

 (2

sin

 (2

 = 
1
 
Rearranging
 
cos

 (2

= 
1
 
– sin

 (2

 
From the double angle identity for cosine
 
Squaring both sides
 
cos

 
(
2
= (1 - 2
sin
2
 
)
 
cos

 
(
2
= 1 - 4
sin
2
 


4
sin
4
 
 
1
 
– sin

 (2

 
=
 1 
 4
sin
2
 


4
sin
4
 
 
=
 
 sin

 (2

 
4
sin
2
 

4
sin
4
 
 
=
 
 sin

 (2

 
4
sin
2
 

(
1 – sin
2
 
)
 
Substituting from
 
=
 
 sin

 (2

 
4
sin
2
 

cos
2
 
 
Taking square root
of both sides
 
=
 
 sin
 (2

 
2
sin
 

cos
 
 
Simplifying
 
1 – sin
2
 
 
 
 
Double angle identities for cosine
 
Pythagorean identity
 
Double angle identity for sine
 
cos
 

sin
 

 = 
1
 
cos
 
(
2

=
 2
cos
 

 1
 
cos
 
(
2

=
 
cos
 

– sin

 
Summary of identities
 
cos
 
(
2

=
 1 
 2
sin
2
 
 
sin
 
(
2

 
=
 2
sin
 

cos
 
 
cos
 
 
sin
 
 
tan
 

=
 
 
 
Using the Pythagorean identity
Given that
 
Substituting the value of sine 
 
cos
 

sin
 

 = 
1
Using identities
sin
 
, and 0
o
 
<
 
 
<
 90
o
Find the exact values of
(a) cos
 
 
Rearranging and simplifying
 
Taking square root
of both sides
 
Solution:
 
 
 
Using the double angle identity for sine
Given that
 
Substituting the value of sin 

and cos 
Using identities
sin
 
, and 0
o
 
<
 
 
<
 90
o
Find the exact values of
(b) sin
 
(2
)
 
Simplifying
 
Solution:
 
sin
 
(
2
 
=
 2
sin
 

cos
 
 
sin
 
(
2
 
sin
 
(
2
 
sin
 
(
2
 
 
 
Using a double angle identity for cosine
Given that
 
Substituting the value of sin 
Using identities
sin
 
, and 0
o
 
<
 
 
<
 90
o
Find the exact values of
(c) cos
 
(2
)
 
Simplifying
 
Solution:
 
cos
 
(
2

=
 1 
 2
sin
2
 
sin
 
(
2
 
 
 
Using identity of tangent
Given that
 
Changing 
 by 2
Using identities
sin
 
, and 0
o
 
<
 
 
<
 90
o
Find the exact values of
(d) tan
 
(2
)
 
Substituting 
sin
 
(
2
  
and 
cos
 
(
2

 
Solution:
sin
 
(
2
 
cos
 
 
sin
 
 
tan
 

=
 
cos
 
(
2
)
 
sin
 
(
2
)
 
tan
 
(
2
)
=
 
tan
 
(
2
)
=
 
Simplifying
 
tan
 
(
2
)
=
 
 
 
Using the double angle identity for sine
Solve the equation
 
Replacing 
sin
 2
x
Using identities when working with equations
sin
 
2
x
sin
 x
for 0
o
 
 
x
 
 360
o
Do not use GDC
 
Rearranging
 
Solution:
 
Using the null factor law
 
sin
 
(
2

 
=
 2
sin
 

cos
 
 
2(
sin
 x
)(
cos
 x
)
 
sin
 x
 
2(
sin
 x
)(
cos
 x
)
 – sin
 x 

 
Factorising
 
(
sin
 x
)(2
cos
 x
– 1
)
 

 
(
sin
 x
) 

 
(2
cos
 x
– 1
)
 

 
or
 
If 
sin
 x
 

 
Then 
x



 
If 2
cos
 x
– 1 

 
So 
x


 
Then 
x





 
 
Thank you for using resources from
https://www.mathssupport.org
If you have a special request, drop us an email
info@mathssupport.org
 
 
For more resources visit our website
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Special identities like the Pythagorean identity and double angle identities for sine and cosine are explored in this content. The Pythagorean identity states that cosine squared plus sine squared equals one, while the double angle identities provide formulas for cosine of double angles. Through the use of these identities, various relationships between trigonometric functions can be derived and utilized to solve problems effectively.

  • Trigonometry
  • Identities
  • Double Angles
  • Pythagorean Identity
  • Sine
  • Cosine

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  1. 28 September 2024 Trigonometric identities LO: To find the Pythagorean identity and trigonometric identities for the sine and cosine of the double angle. To use those identities to solve problems. www.mathssupport.org www.mathssupport.org

  2. Pythagorean identity In this section we are going to look at special kinds of equations called identities y From the unit circle we found that: OC = cos BC = sin sin = y cos = x (cos sin ) B 1 sin Since it is a right angled triangle we can use Pythagoras theorem and say that (cos ) + (sin )2 = 1 cos + sin = 1 This called The Pythagorean identity A C 0 x cos We can also say that sin Another identity tan = cos www.mathssupport.org www.mathssupport.org

  3. Double angle identity for cosine In the following diagram, we draw the reflection of the angle in the fourth quadrant. The length AC A 1 We can see that the angle AOB = 2 sin y = BC = sin So, AB = AC + BC = 2sin sin C O x The length AB can be found using the cosine rule in the AOB. Squaring both sides 4sin2 = 2 - 2cos(2 ) Rearranging 2cos(2 ) = 2 - 4sin2 Dividing by 2 cos(2 ) = 1 - 2sin2 1 B AB2 = AO2 + BO2 2(AO)(BO)cos(2 ) AB2 = 12 + 12 2(1)(1)cos(2 ) AB = 2 2cos(2?) Now we have two expressions for AB 2sin = 2 2cos(2?) This is one identity for the cosine of the double angle www.mathssupport.org www.mathssupport.org

  4. Double angle identity for cosine We are going to use this identity to find more identities for the cosine of the double angle cos(2 ) = 1 - 2sin2 We will use the Pythagorean identity cos + sin = 1 Rearranging the identity Substituting in the identity sin = 1 cos cos(2 ) = 1 2(1 cos ) Expanding brackets Simplifying and rearranging This is another identity for the cosine of the double angle cos(2 ) = 1 2 + 2cos cos(2 ) = 2cos 1 www.mathssupport.org www.mathssupport.org

  5. Double angle identity for cosine We are going to use this last identity to find more identities for the cosine of the double angle cos(2 ) = 2cos 1 We will use the Pythagorean identity cos + sin = 1 We can substitute the identity into the identity cos(2 ) = 2cos (cos + sin ) Expanding brackets cos(2 ) = 2cos cos sin Simplifying cos(2 ) = cos sin This is another identity for the cosine of the double angle www.mathssupport.org www.mathssupport.org

  6. Double angle identity for sine Now we are going to find a double-angle identity for sine We will use the Pythagorean identity cos (2 )+ sin (2 ) = 1 Rearranging cos (2 )= 1 sin (2 ) From the double angle identity for cosine cos + sin = 1 We can say cos(2 ) = 1 - 2sin2 cos (2 ) = (1 - 2sin2 ) cos (2 ) = 1 - 4sin2 + 4sin4 1 sin (2 )= 1 4sin2 + 4sin4 =sin (2 ) 4sin2 4sin4 =sin (2 ) 4sin2 (1 sin2 ) =sin (2 ) 4sin2 cos2 2sin cos Squaring both sides Equating these equations Simplifying Factorising Substituting from Taking square root of both sides 1 sin2 =sin(2 ) www.mathssupport.org www.mathssupport.org

  7. Summary of identities sin tan = cos Pythagorean identity cos + sin = 1 Double angle identities for cosine cos(2 ) = 1 2sin2 cos(2 ) = 2cos 1 cos(2 ) =cos sin Double angle identity for sine sin(2 ) = 2sin cos www.mathssupport.org www.mathssupport.org

  8. Using identities sin =3 4, and 0o< < 90o Given that Find the exact values of (a) cos Solution: Using the Pythagorean identity cos + sin = 1 Substituting the value of sine 2= 1 3 4 cos + Rearranging and simplifying 9 cos = 1 16 cos = 7 16 Taking square root of both sides 7 cos = 4 www.mathssupport.org www.mathssupport.org

  9. 7 Using identities cos = 4 sin =3 4, and 0o< < 90o (b) sin(2 ) Given that Find the exact values of Solution: Using the double angle identity for sine sin(2 )= 2sin cos Substituting the value of sin and cos sin(2 ) = 2 3 4 7 4 Simplifying 6 7 16 sin(2 ) = sin(2 ) = 3 7 8 www.mathssupport.org www.mathssupport.org

  10. 7 Using identities cos = 4 sin =3 sin(2 )= 3 7 4, and 0o< < 90o (c) cos(2 ) Given that 8 Find the exact values of Solution: Using a double angle identity for cosine cos(2 ) = 1 2sin2 Substituting the value of sin 2 3 4 cos(2 ) = 1 2 Simplifying 9 cos(2 ) = 1 2 16 9 8 cos(2 ) = 1 cos(2 ) = 1 8 www.mathssupport.org www.mathssupport.org

  11. 7 Using identities cos = 4 sin =3 sin(2 )= 3 7 cos(2 ) = 1 4, and 0o< < 90o (d) tan(2 ) Given that 8 Find the exact values of Solution: 8 Using identity of tangent sin tan = cos sin(2 ) Changing by 2 tan(2 )= 3 7 8 cos(2 ) tan(2 )= Substituting sin(2 )and cos(2 ) 1 8 tan(2 )=3 7 Simplifying 8 8 1 tan(2 )= 3 7 www.mathssupport.org www.mathssupport.org

  12. Using identities when working with equations Solve the equation Do not use GDC Solution: for 0o x 360o sin2x = sin x Using the double angle identity for sine sin(2 )= 2sin cos 2(sin x)(cos x)= sin x 2(sin x)(cos x) sin x = (sin x)(2cos x 1)= (sin x) = If sin x = Then x = If 2cos x 1 = Then cos x =1 Then x = Replacing sin 2x Rearranging Factorising or Using the null factor law (2cos x 1)= 2So x = www.mathssupport.org www.mathssupport.org

  13. Thank you for using resources from A close up of a cage Description automatically generated For more resources visit our website https://www.mathssupport.org If you have a special request, drop us an email info@mathssupport.org www.mathssupport.org www.mathssupport.org

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