Oxidation and Reduction in Biotechnology through Erasmus+ Sustainability

 
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Renée Ristl
 
Evelin Szabados
 
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Oxidation: electron donation
Reduction: electron acceptance
 
Example:
Oxidation: 2 O
2-
 
 O
2 
+ 4 e
-
Reduction: Fe
3+
 + e
-
 
 Fe
2+
Both, oxidation and reduction have to occur
together!
 
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Often there aren‘t “real“ molecular charges – e.g.
glucose or water
Atoms possess an oxidation state, described by
oxidation numbers
H
2
, O
2
 are neutral 
 oxidation number 0
In water (H
2
O), the H has got the oxidation number
+1, the O: -2
In organic compounds, the oxidation number of C has
to be calculated
 
C
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:
 
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C
 
E.g. glucose:
 
-
2
 
+
1
 
+1 – 2 
= -1
C is neutral
 it needs 
+1
 to equalise
 
+
1
 
E
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p
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Oxidation: 2 H
2
 
 4 H
+
 + 4 e
-
 
0
 
+1
 
Reduction:  O
2
 + 4 e
-
 
 2 O
2-
 
0
 
-2
 
R
 
+1
 
 
R
 
+3
 
+ 2 e
-
 
Oxidation:
 
Together: 2 H
2
 + O
2
 
 2 H
2
O
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Explore the concept of oxidation and reduction in biotechnology with the help of Erasmus+ Sustainability, discussing electron donation, electron acceptance, oxidation numbers, and calculation examples. Learn how these processes work together for sustainable biotechnological applications.

  • Biotechnology
  • Sustainability
  • Oxidation
  • Reduction
  • Erasmus

Uploaded on Aug 11, 2024 | 0 Views


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  1. Erasmus+ Sustainability by Biotechnology Oxidation and Reduction Ren e Ristl Evelin Szabados

  2. Definition Oxidation: electron donation Reduction: electron acceptance Example: Oxidation: 2 O2- O2 + 4 e- Reduction: Fe3+ + e- Fe2+ Both, oxidation and reduction have to occur together!

  3. Oxidation numbers Often there aren t real molecular charges e.g. glucose or water Atoms possess an oxidation state, described by oxidation numbers H2, O2 are neutral oxidation number 0 In water (H2O), the H has got the oxidation number +1, the O: -2 In organic compounds, the oxidation number of C has to be calculated

  4. Calculation: Oxidation number of C E.g. glucose: + 1 -2 + 1 +1 2 = -1 C is neutral it needs +1 to equalise

  5. Examples +1 0 Oxidation: 2 H2 4 H+ + 4 e- Together: 2 H2+ O2 2 H2O -2 0 Reduction: O2 + 4 e- 2 O2- +3 +1 Oxidation: + 2 e- R R

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