Matrix Multiplication and Dimensions Guide

FP1 Matrices Introduction
BAT multiply matrices
 
These numbers 
must
 be the
same for the multiplication to
be possible
 
These numbers will give the
dimensions of the answer
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You multiply each 
row
 in the first matrix, by each 
column
 in the second matrix
The product will have the same number of rows as the first matrix, and
the same number of columns as the second
 
To multiply matrices you
first multiply
corresponding elements of
the rows and columns, then
add them up (you’ll get it
with practice!)
 
Then once you have done
all the columns, do the
same thing, but using the
second row…
 
After this, work out each
part, and you then have the
final matrix answer!
Dimensions for AB
(2 x 2) x (2 x 1) = (2 x 1)
Dimensions for BA
(2 x 1) x (2 x 2) = 
not possible 
 
Calculating 
AB
 
Multiply the first
row by each column
as in the previous
example
 
You always fill in
the top row of the
answer first
 
 A quick check –
you have probably
done this correctly
if the highlighted
(green) numbers
are the same!
Dimensions for AB
(2 x 2) x (2 x 2) = (2 x 2)
Dimensions for BA
(2 x 2) x (2 x 2) = (2 x 2)
Calculating 
BA
 
Multiply the first
row by each column
as in the previous
example
 
You always fill in
the top row of the
answer first
 
 A quick check –
you have probably
done this correctly
if the highlighted
(green) numbers
are the same!
 
AB =   dimensions (1x3) x (1x2)
not possible
 
As the central numbers are
not equal, these matrices
cannot be combined
Calculating 
BCA
This can be done in one of two ways
1)   (
BC
)
A
Multiply B by C, and the answer to
that by A (in that order)
Matrices - multiplying
Find (where possible):
i)
 AB
  
ii) BA
  
iii)  BC
  
iv)   CB
v)  DA
  
vi)  AD
  
vii)   CD
  
viii)   DC
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Matrices - multiplying
Find (where possible):
v)  DA
  
vi)  AD
  
vii)   CD
  
viii)   DC
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Matrices - multiplying
Find (where possible):
v)  DA
  
vi)  AD
  
vii)   CD
  
viii)   DC
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As 
BA
 = 0, the
implication is that
–b + 2a = 0
 
We know from before that
2a = b so we can replace the
b terms…
Summary
Crucial points:
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END
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Learn how to multiply matrices, determine matrix dimensions, and distinguish between commutative and non-commutative operations. Gain insight into the practical application of matrix algebra with step-by-step examples.

  • Matrix algebra
  • Multiplication
  • Dimensions
  • Matrices
  • Commutative

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  1. FP1 Matrices Introduction BAT multiply matrices

  2. Matrix multiplication These numbers will give the dimensions of the answer ? ? = ? ? ? ? ? ? ? These numbers must be the same for the multiplication to be possible You multiply each row in the first matrix, by each column in the second matrix The product will have the same number of rows as the first matrix, and the same number of columns as the second

  3. WB 7 ? =1 2 4 ? = 3 Find AB and BA 3 2 Dimensions for AB (2 x 2) x (2 x 1) = (2 x 1) 1 3 2 4 3 2 = To multiply matrices you first multiply corresponding elements of the rows and columns, then add them up (you ll get it with practice!) 1 3 + ( 2 2) 3 3 + (4 2) 3 + ( 4) Then once you have done all the columns, do the same thing, but using the second row 9 + (8) ?? = 7 After this, work out each part, and you then have the final matrix answer! 1 Dimensions for BA (2 x 1) x (2 x 2) = not possible

  4. WB 8a ? = 1 0 3 ? =4 1 Find AB and BA 2 2 0 Calculating AB Dimensions for AB (2 x 2) x (2 x 2) = (2 x 2) 1 2 0 3 4 0 1 = 2 Multiply the first row by each column as in the previous example 1 4 + (0 0) 1 1 + (0 2) 2 1 + (3 2) 2 4 + (3 0) You always fill in the top row of the answer first 4 + (0) 1 + (0) 8 + (0) 2 + ( 6) A quick check you have probably done this correctly if the highlighted (green) numbers are the same! ?? = 4 1 4 8

  5. WB 8b ? = 1 0 3 ? =4 1 Find AB and BA 2 2 0 Calculating BA Dimensions for BA (2 x 2) x (2 x 2) = (2 x 2) 4 0 1 1 2 0 3 = 2 Multiply the first row by each column as in the previous example 4 0 + (1 3) 4 1 + (1 2) 0 0 + ( 2 3) 0 1 + ( 2 2) You always fill in the top row of the answer first 4 + (2) 0 + (3) 0 + ( 6) 0 + ( 4) A quick check you have probably done this correctly if the highlighted (green) numbers are the same! ?? = 2 3 4 6 AB ?? Multiplication using matrices is NOT commutative This means the order of multiplication does matter as a different order gives different answers!

  6. WB 9abc Find a) AB 2? =4 2? = 3 ? = 1 1 5 b) BC c) CA d) BCA AB = dimensions (1x3) x (1x2) not possible As the central numbers are not equal, these matrices cannot be combined 4 5 = BC = 3 12 + ( 10) = 2 2 2 = 4 1 4 1 5 1 4 2 5 2 CA = 4 1 1 5 1 5 = 4 4 5 8 10 5

  7. WB 9d Find a) AB 2? =4 2? = 3 ? = 1 1 5 b) BC c) CA d) BCA Calculating BCA This can be done in one of two ways 1) (BC)A Multiply B by C, and the answer to that by A (in that order) (1) ?? = 2 ??? = 2 1 1 2 2) B(CA) Multiply C by A, and multiply B by the answer to that (in that order) ??? = 2 2 4 4 4 5 8 10 (2) ?? = 5 Remember you cannot change the order, so for method 2, do not do CA and then x B after, the B must go at the front! 4 4 5 8 ??? = 3 2 5 10 ??? = 2 2 4

  8. Matrices - multiplying WB 10abcd Use each row of the first matrix with each column of the second matrix. The result gives you the element in row a column b of the product matrix. 1 0 2 1 3 4 2 3 5? =3 2? = 3 8 2 4 0 ? = 2? = 1 1 1 Find (where possible): i) AB v) DA ii) BA vi) AD iii) BC vii) CD iv) CB viii) DC 2 3 5 3 1 8 9 2 10 18 AB = 2 = 1 2 3 5 = BA =3 8 2 4 49 7 1 1 2 BC =3 8 3 1 2 4 0 2 = 1 38 6 16 4 1 2 5 CB = 3 2 4 0 3 1 8 2= not possible 1 2 To multiply matrices what must be true?

  9. Matrices - multiplying WB 10ef Use each row of the first matrix with each column of the second matrix. The result gives you the element in row a column b of the product matrix. 1 0 2 1 3 4 2 3 5? =3 2? = 3 8 2 4 0 ? = 2? = 1 1 1 Find (where possible): v) DA vi) AD vii) CD viii) DC 2 3 10 10 6 8 1 0 2 1 3 4 3 1 8 DA = 2 = 1 0 2 1 3 4 AD =3 8 = not possible 1 2 BC =3 8 3 1 2 4 0 2 = 1 38 6 16 4 1 2 5 To multiply matrices what must be true?

  10. Matrices - multiplying WB 10gh Use each row of the first matrix with each column of the second matrix. The result gives you the element in row a column b of the product matrix. 1 0 2 1 3 4 2 3 5? =3 2? = 3 8 2 4 0 ? = 2? = 1 1 1 Find (where possible): v) DA vi) AD vii) CD viii) DC 1 0 2 1 3 4 3 3 9 3 CD = 3 2 4 0 = 1 2 1 0 2 1 3 4 4 3 2 2 12 20 2 3 1 2 4 0 DC = 2 = 6 8 To multiply matrices what must be true?

  11. WB 11 ? =1 Given that BA = (0), show that AB= 2? ? = ? 2 ? 2 2? 2?2 1 ? = ? + 2? ?? = ? 2 As BA = 0, the implication is that b + 2a = 0 ? + 2? = 0 2? = ? ?? = 1 ? ?? 2 2? 2 = ? We know from before that 2a = b so we can replace the b terms ? ?? = 2? 2 2? 2?2

  12. Summary Crucial points: Make sure that you can do matrix multiplication confidently Remember that matrix multiplication is NOT commutative AB BA

  13. END

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