Gravitational Potential Energy and Negative Potential Energy

 
1
 
Last Time
:  Centripetal Acceleration, Newtonian
 
Gravitation
 
Today
:
  
Two practice multiple choice problems
  
Gravitational Potential Energy (a different look)
  
Kepler’s Laws of Planetary Motion
 
HW #6 due tonight 11:59 p.m.
 
Exam #2 Details
 :
Thursday, October 21, regular class time (75 minutes)
Closed-book, closed-note
You 
CAN AND SHOULD
 bring a calculator
Exam #2 Formula Sheet posted on Blackboard
  
Will be provided
  
(
not allowed to bring your own copy
)
Today’s new material 
NOT
 on the exam
 
Multiple Choice:  5 
 5 points  =  25 points
Short Answer(s):  10 points
Problems:  
3 problems
, 65 points
Bonus Problem:  5 points
Possible Total:  105/100
 
2
 
Typo Last Time
 
3
 
should be …
 
G = 6.673 
 10
−11
 kg
−1
 m
3
 s
−1
 
G = 6.673 
 10
−11
 kg
−1
 m
3
 s
−2
 
Conceptual Question #1
 
4
 
(practice for exam)
 
A merry-go-round rotates with
constant angular speed.  As a rider
moves from the edge towards the
center, what happens to the
magnitude of the centripetal force
that must be exerted on her ?
 
Mall of America (Minneapolis, MN)
 
(a) It increases.
 
(b) It is not zero, but remains the same.
 
(c) It decreases.
 
(d) It is always zero, because its angular speed is constant.
 
(e) It increases or decreases, depending on the direction of
rotation (CCW or CW).
 
Conceptual Question #2
 
5
 
(practice for exam)
 
The gravitational force exerted on an
astronaut on Earth’s surface before
launch is 650 N downwards.  On the
International Space Station, is the
gravitational force on the astronaut …
 
(a) Larger
 
(b) Exactly the same
 
(c) Smaller
 
(d) Zero
 
Gravitational Potential Energy
 
6
 
So far, we have calculated the
potential energy of an object
above the Earth’s surface as :
 
h
 
m
 
g
 
But, we learned that the acceleration due to gravity decreases
the farther we move away from the surface of the Earth.
 
force
 
distance
 
high above the Earth !
 
PE  =  m 
 
g 
 
h
 
Negative Potential Energy ?
 
7
 
PE = 0  at  r 
 
 
PE is a 
MAXIMUM
 at 
r 
 
 
R
E
 
M
E
 
10
6
 m
 
10
6
 m
 
Consider an object with a mass of 1.0-kg falling
towards Earth, which is initially 
2 
 10
6
 m 
above
the surface of Earth at rest.  What is its speed
when it is 
1
 
 10
6
 m 
above the Earth ?
 
How much work was done by gravity ?
 
For r < 
, PE < 0, becomes more
negative as move towards Earth
 
What About PE = mgh ?
 
8
 
Is our “new” formula for gravitational PE consistent with PE = mgh
on the surface of the Earth ?
 
Earth’s surface
 
h
 
#2
 
#1
 
What Must the Speed of a Rocket be to
 
9
 
Escape
 Earth’s Gravity ?
 
At launch
:
 
At 
 
:
 
“barely”
makes it to 
 
Energy Conservation
 :
 
11.2 km/s
on Earth
 
[25054 mph]
 
Example
 
10
 
A space capsule with mass 1000 kg is launched from the surface
of Earth at the escape speed v
esc
.  What will its speed be when it
is 10
3
 km above the surface of the Earth ?
 
Kepler’s Laws of Planetary Motion
 
11
 
German mathematician and
astronomer, 1571 – 1630
 
Work provided the grounds
for Newton’s theory of
gravitation
 
Before Kepler’s Laws …
 
“Geocentric Model”:  Earth is center of universe
 
Greek astronomer Ptolemy, 2
nd
 century A.D. – 1400s
 
“Heliocentric Model”:  Earth/Planets orbit Sun in circular orbits
 
Copernicus, 1473 – 1543
 
Kepler analyzed data for 16 years, and deduced a mathematical
model for the motion of planets about the Sun
 
Kepler’s Laws of Planetary Motion
 
12
 
All planets move in elliptical orbits about the Sun (not circular
orbits), with the Sun at one of the focal points.
 
#1
 
Ellipse is a curve drawn so that the sum of the
distances from any point on the curve, to two internal
points called the focal points, is constant.
 
p
 + 
q
 = constant
 
[for any point on the ellipse]
Because orbit is an ellipse, the Planet’s
distance from the Sun is constantly changing !
 
Kepler’s Laws of Planetary Motion
 
13
 
A line drawn from the Sun to any planet sweeps out equal
areas in equal time intervals.
 
#2
 
According to this law, the if the areas above are equal,
the planet will take the same amount of time to move
from A
B as it does to move from C
D.
Planets move faster the closer
they are to the Sun !
 
[
Also follows from conservation of angular momentum, later 
…]
 
Kepler’s Laws of Planetary Motion
 
14
 
For circular orbits, the square of the orbital period of any
Planet (or a satellite) is proportional to the cube of the
average distance from the Planet to the Sun.
 
#3
 
Period T = time required for one revolution = 2
π
r/v
 
M
S
:  mass of the Sun = 1.991 
 10
30
 kg
 
r :  radius of circular orbit
For elliptical orbits, r must be replaced with a,
the semimajor axis (half the longest distance).
 
2a
 
r
 
OR
 the object about which it is orbiting
 
Example
 
15
 
A satellite moves in a circular orbit around the Earth at a
speed of 5000 m/s.  Determine:
 
(a) The satellite’s altitude above the surface of the Earth.
 
(b) The period of the satellite’s orbit.
 
“Geosynchronous Orbits”
 
16
 
A satellite in a geosynchronous orbit remains at the same
location relative to a location on the Earth.  These are used in
telecommunications.
 
This can only occur if the satellite’s orbital period is the same
as the Earth’s period of rotation, 24.0 hours.
 
(a) At what distance from the center of the Earth must the
satellite be?
 
(b) What is the satellite’s orbital speed?
 
Next Lecture Class
 
8.1 – 8.2 :
 
Torque and Equilibrium
 
17
Slide Note
Embed
Share

Exploring the concept of gravitational potential energy beyond the surface of Earth, understanding how potential energy varies with distance from the Earth's center, and delving into the significance of negative potential energy at certain points. Learn about the calculations involved, including the equation for gravitational potential energy and its implications for objects at different distances from Earth.

  • Gravitational Potential Energy
  • Negative Potential Energy
  • Distance from Earth
  • Energy Calculations
  • Earths Surface

Uploaded on Sep 23, 2024 | 0 Views


Download Presentation

Please find below an Image/Link to download the presentation.

The content on the website is provided AS IS for your information and personal use only. It may not be sold, licensed, or shared on other websites without obtaining consent from the author. Download presentation by click this link. If you encounter any issues during the download, it is possible that the publisher has removed the file from their server.

E N D

Presentation Transcript


  1. Last Time: Centripetal Acceleration, Newtonian Gravitation Today: Two practice multiple choice problems Gravitational Potential Energy (a different look) Kepler s Laws of Planetary Motion HW #6 due tonight 11:59 p.m. 1

  2. Exam #2 Details : Thursday, October 21, regular class time (75 minutes) Closed-book, closed-note You CAN AND SHOULD bring a calculator Exam #2 Formula Sheet posted on Blackboard Will be provided (not allowed to bring your own copy) Today s new material NOT on the exam Multiple Choice: 5 5 points = 25 points Short Answer(s): 10 points Problems: 3 problems, 65 points Bonus Problem: 5 points Possible Total: 105/100 2

  3. Typo Last Time G = 6.673 10 11 kg 1 m3 s 1 should be G = 6.673 10 11 kg 1 m3 s 2 3

  4. Conceptual Question #1 (practice for exam) A merry-go-round rotates with constant angular speed. As a rider moves from the edge towards the center, what happens to the magnitude of the centripetal force that must be exerted on her ? Mall of America (Minneapolis, MN) (a) It increases. (b) It is not zero, but remains the same. (c) It decreases. (d) It is always zero, because its angular speed is constant. (e) It increases or decreases, depending on the direction of rotation (CCW or CW). 4

  5. Conceptual Question #2 (practice for exam) The gravitational force exerted on an astronaut on Earth s surface before launch is 650 N downwards. On the International Space Station, is the gravitational force on the astronaut (a) Larger (b) Exactly the same (c) Smaller (d) Zero 5

  6. Gravitational Potential Energy So far, we have calculated the potential energy of an object above the Earth s surface as : PE = m g h m g h force distance But, we learned that the acceleration due to gravity decreases the farther we move away from the surface of the Earth. mg F high above the Earth ! For objects high above the Earth, the gravitational potential energy associated with a mass m at a distance r from the center of the Earth is m M G PE = ME : Earth s mass [ SI: Joules ] E r 6

  7. Negative Potential Energy ? PE = 0 at r PE is a MAXIMUM at r For r < , PE < 0, becomes more negative as move towards Earth M m = E PE G r Consider an object with a mass of 1.0-kg falling towards Earth, which is initially 2 106 m above the surface of Earth at rest. What is its speed when it is 1 106 m above the Earth ? 106 m 106 m RE How much work was done by gravity ? ME 7

  8. What About PE = mgh ? Is our new formula for gravitational PE consistent with PE = mgh on the surface of the Earth ? M m + = #2 E PE G 2 ( ) R h E M m = E PE G 1 R h E 1 1 GM mh ) = GM = E PE PE m 2 1 E + + ( R h R R h R #1 E E E E Earth s surface 1 1 GM = = E PE PE m h mgh 2 1 + 2 2 E ( ) R R h R R E E E 8

  9. What Must the Speed of a Rocket be to Escape Earth s Gravity ? The escape speed of a rocket is the speed with which a rocket needs to be launched, in order to escape Earth s gravity, and reach . At : At launch: Energy Conservation : 1 M m M m = = = 0 2 esc PE 0 E E PE G mv G 2 R R E E 1mv KE = 2 esc = 0 11.2 km/s on Earth [25054 mph] KE barely makes it to GM 2 2 esc= E v R E 9

  10. Example A space capsule with mass 1000 kg is launched from the surface of Earth at the escape speed vesc. What will its speed be when it is 103 km above the surface of the Earth ? 10

  11. Keplers Laws of Planetary Motion German mathematician and astronomer, 1571 1630 Work provided the grounds for Newton s theory of gravitation Before Kepler sLaws Geocentric Model : Earth is center of universe Greek astronomer Ptolemy, 2nd century A.D. 1400s Heliocentric Model : Earth/Planets orbit Sun in circular orbits Copernicus, 1473 1543 Kepler analyzed data for 16 years, and deduced a mathematical model for the motion of planets about the Sun 11

  12. Keplers Laws of Planetary Motion All planets move in elliptical orbits about the Sun (not circular orbits), with the Sun at one of the focal points. #1 Ellipse is a curve drawn so that the sum of the distances from any point on the curve, to two internal points called the focal points, is constant. p + q = constant [for any point on the ellipse] Because orbit is an ellipse, the Planet s distance from the Sun is constantly changing ! 12

  13. Keplers Laws of Planetary Motion A line drawn from the Sun to any planet sweeps out equal areas in equal time intervals. #2 According to this law, the if the areas above are equal, the planet will take the same amount of time to move from A B as it does to move from C D. Planets move faster the closer they are to the Sun ! [Also follows from conservation of angular momentum, later ] 13

  14. Keplers Laws of Planetary Motion 2a r For circular orbits, the square of the orbital period of any Planet (or a satellite) is proportional to the cube of the average distance from the Planet to the Sun. #3 MS: mass of the Sun = 1.991 1030 kg OR the object about which it is orbiting 2 4 S = 2 3 T r GM r : radius of circular orbit Period T = time required for one revolution = 2 r/v For elliptical orbits, r must be replaced with a, the semimajor axis (half the longest distance). 14

  15. Example A satellite moves in a circular orbit around the Earth at a speed of 5000 m/s. Determine: (a) The satellite s altitude above the surface of the Earth. (b) The period of the satellite s orbit. 15

  16. Geosynchronous Orbits A satellite in a geosynchronous orbit remains at the same location relative to a location on the Earth. These are used in telecommunications. This can only occur if the satellite s orbital period is the same as the Earth s period of rotation, 24.0 hours. (a) At what distance from the center of the Earth must the satellite be? (b) What is the satellite s orbital speed? 16

  17. Next Lecture Class 8.1 8.2 : Torque and Equilibrium 17

More Related Content

giItT1WQy@!-/#giItT1WQy@!-/#giItT1WQy@!-/#giItT1WQy@!-/#giItT1WQy@!-/#