Determination of Acetic Acid Content in Vinegar Experiment

The experiment aims to measure the total acid concentration in a specific brand of vinegar through a titration process using NaOH solution. The procedure involves titrating the vinegar solution with NaOH until a pink color appears, calculating the concentration of acetic acid, and determining the percentage of acetic acid in the vinegar sample. The example provided demonstrates the calculation steps involved in determining the acetic acid content in vinegar.

• Vinegar Experiment
• Acetic Acid Determination
• Titration Process
• Chemistry Lab
• Acid Concentration

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Uploaded on Jul 25, 2024 | 2 Views

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1. Determination of Acetic Acid content Vinegar

2. What is Vinegar ? is formed by aerobic bacteria oxidizing grain alcohol to acetic acid and water. More generally, vinegar can be defined as a solution composed of acetic acid [ CH3COOH], water and perhaps other substances. this solution must contain at least four grams of acetic acid per 100 ml solution.

3. The objective of this experiment is to measure the total acid concentration in a specific brand of vinegar.

5. Procedure: 1.Fill the burette with 0.1N of NaOH solution to be used as a titrant. 2.Pipette 25 ml of commercial vinegar into the 250 ml volumetric flask and complete the volume by distilled water. 3.Put 10 ml of solution (vinegar solution) in a conical flask and add 2 drops of phenolphthalein indicator.

6. 4.Titer with NaOH solution until formed pink color. 5.Repeat the titration process. 6.Calculate the concentration of acetic acid in 250 ml ( N x V ) CH3COOH= ( N x V) NaOH NCH3COOHx eq.wt = wt. of CH3COOH in 1 liter NCH3COOHx eq.wt x (250/1000) = wt. of CH3COOH in 250 ml 7.Calculate the % acetic acid in vinegar %(w/w) = (wt. acetic acid / wt. of vinegar ) x 100

7. Example ( N x V ) CH3COOH= ( N x V) NaOH N *10 = 0.1 * 14 N=0.14 eq/L NCH3COOHx eq.wt x (250/1000) = wt. of CH3COOH in 250 ml 0.14 * 60* 0.25 = wt. of CH3COOH in 250 ml wt. of CH3COOH in 250 ml = 2.1 gm. %(w/w) = (wt. acetic acid / wt. of vinegar ) x 100 %(w/w) = (2.1/ 25) * 100 %(w/w) =8.4