Understanding Wheatstone Bridge Circuit for Resistance Measurement
Wheatstone Bridge is a precise instrument for measuring unknown electrical resistances by balancing a bridge circuit. This practical application involves using resistors of known values to determine the unknown resistance. The voltage division formula plays a key role in calculating the unknown resistance. Additionally, the concept extends to strain gauges where small strains produce measurable voltage outputs. Explore the principles and applications of Wheatstone Bridge in resistance measurement and strain gauge sensors.
- Wheatstone Bridge
- Resistance Measurement
- Voltage Division Formula
- Strain Gauge
- Electrical Engineering
Download Presentation
![](/assets/img/so-down.gif)
Please find below an Image/Link to download the presentation.
The content on the website is provided AS IS for your information and personal use only. It may not be sold, licensed, or shared on other websites without obtaining consent from the author. Download presentation by click this link. If you encounter any issues during the download, it is possible that the publisher has removed the file from their server.
E N D
Presentation Transcript
Practical Application: Voltage Division Formula The Wheatstone Bridge A Wheatstone bridge is a measuring instrument used to measure an unknown electrical resistance. Rx is the unknown resistance to be measured; R1, R2 and R3 are resistors of known resistance and the resistance of R3 is adjustable. Unknown Resistor V ariable resistor
Practical Application - Voltage Division Formula - When all the resistors are equal to R: ????= 0
Practical Application - Voltage Division Formula - When all the resistors are equal to R: ????= 0
Practical Application - Voltage Division Formula - With strain gage is connected, ? 4?+2 ?? ????=
Practical Application- Strain Gauge - Voltage Division Formula - The output of the bridge changes nonlinearly with applied force. However, R is several hundred ohms, while R is typically 0.01 , a factor of 10,000 times smaller. So, we assume that ? ? 4?? 4?+2 ?? ????= ???? Small strain produced measurable voltage