Color Combinations with Chemical Reactions
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Besat 2
Alireza Hamidian
Problem:
You are given aqueous solutions of potassium
dichromate (K
2
Cr
2
O
7
) and copper (ll) sulfate
(CuSO
4
). By mixing these two solutions in any
combination with colorless solutions of your
choice, obtain as many test tubes showing
distinctly different colors as possible.
Initial:
K
2
Cr
2
O
7
+ CuSO
4
= Yellow
Blue + orange = light purple
K
2
Cr
2
O
7
+CuSo
4
= K
2
SO
4
+ CuCr
2
O
7
????
Colorless
Yellow
Then:
KOH + solution = Green not dissolved salt(Green)
2KOH + CuSO
4
= Cu(OH)
2
+ K
2
SO
4
And it happened again with NaOH.
Green
We also used NH
4
OH
But nothing happened;
So we conclude that no reaction
will happen.
Thanks for your attention!
Explore various color combinations using aqueous solutions of potassium dichromate, copper sulfate, and other colorless solutions. By mixing these solutions, generate distinct colors in test tubes through chemical reactions. Different hues such as yellow, blue, orange, light purple, and green are achieved by combining different chemicals. Observations on reactions with potassium hydroxide (KOH), sodium hydroxide (NaOH), and ammonium hydroxide (NH4OH) are made to understand the chemical processes further.
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Presentation Transcript
PROBLEM NO.23 COLORS OF THE RAINBOW Besat2 AlirezaHamidian
Problem: You are given aqueous solutions of potassium dichromate (K2Cr2O7) and copper (ll) sulfate (CuSO4). By mixing these two solutions in any combination with colorless solutions of your choice, obtain as many test tubes showing distinctly different colors as possible.
Initial: K2Cr2O7+ CuSO4= Yellow Blue + orange = light purple ???? K2Cr2O7+CuSo4= K2SO4+ CuCr2O7 Yellow Colorless
Then: KOH + solution = Green not dissolved salt(Green) 2KOH + CuSO4 = Cu(OH)2 + K2SO4 Green And it happened again with NaOH.
We also used NH4OH But nothing happened; So we conclude that no reaction will happen.
