Soil Phase Relationships and Properties

 
Chapter
 
3
 
3. Soil phase
 
relationships
 
38
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
Contents of 
chapter
 
3
 
3.1
 
Introduction
Soil is 
composed 
of 
solids, 
liquids, 
and 
gases 
(see 
Figure 3.1a). 
The 
solid phase 
may 
be 
minerals,
organic matter, 
or both. The 
spaces between 
the 
solids 
(soil 
particles) are called 
voids. Water is 
often
the 
predominant 
liquid and 
air 
is the 
predominant 
gas. 
We 
will 
use the terms 
water and air 
instead of
liquid 
and 
gas. 
The 
soil water 
is 
called 
pore 
water and plays 
a 
very 
important role in the 
behaviour 
of
soils under 
load. 
If 
all 
the voids are filled 
by 
water, the 
soil 
is 
saturated. Otherwise, 
the 
soil 
is
unsaturated. 
If 
all 
the voids 
are filled with air, 
the 
soil 
is 
said 
to be
 
dry.
 
Figure 3.1 
Soil
 
phases
 
We 
can idealize 
the three 
phases 
of 
soil, as shown 
in 
Figure 
3.1b. The 
physical parameters 
of 
soils 
are
influenced 
by 
the 
relative proportions 
of 
each 
of these 
phases. 
The 
total 
volume of the 
soil 
is the sum
of the volume of 
solids 
(
V
s
), volume of 
water 
(
V
w
), 
and 
volume of 
air 
(
V
a
); 
that
 
is,
 
 
 
where
 
 
 
is the volume of voids. 
The weight 
of the 
soil 
is 
the sum 
of the 
weight 
of 
solids 
(w
s
) 
and 
the 
weight 
of
water (w
w
). 
The 
weight 
of 
air 
is 
negligible.
 
Thus,
 
 
 
The 
following 
definitions 
have 
been 
established 
to 
describe 
the 
proportion 
of 
each
 
constituent
in a 
soil. Each equation can 
be 
presented with different variables. 
The most popular 
and convenient
forms are given. You should 
try to memorize these
 
relationships.
 
3.2 Water content (w) 
is the 
ratio, often expressed as 
a 
percentage, 
of the 
weight 
of 
water
to the 
weight 
of
 
solids:
 
 
 
 
 
If 
organic 
matter is present in a 
soil, 
it may oxidize 
and 
decompose 
at 
110
 
±5°C
 
 
3.
Void 
ratio 
(e) 
is 
the 
ratio 
of the volume of void 
space 
to the volume of 
solids. Void
ratio 
is 
usually expressed as 
a 
decimal
 
quantity:
0< 
e 
<
 
 
4.
Porosity 
(n) 
is the 
ratio 
of the volume of voids to the total 
volume. 
Porosity is usually
expressed as 
a
 
percentage:
 
 
 
0< 
n 
<
 
1
 
39
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
 
Porosity 
and 
void 
ratio 
are 
related 
by 
the
 
expressions
 
 
 
 
 
 
Prove 
Equations 
3.7 
and 
3.8 ?
 
H.W
 
3.5 Specific gravity 
(Gs) 
is 
the 
ratio 
of the 
weight 
of the 
soil 
solids to the 
weight 
of water
of 
equal
 
volume:
 
 
 
 
 
 
 
 
 
3.6 Mass Specific gravity
 
(G
m
)
 
 
The 
‘Mass specific gravity’ 
of a soil may be 
defined as 
the 
ratio 
of mass or bulk unit 
weight 
of 
soil 
to
the unit 
weight 
of water 
at 
the 
standard 
temperature 
(4°C). 
This is 
denoted 
by 
the letter 
symbol 
G
m 
and
is 
given
 
by:
 
 
 
 
3.7 Degree 
of 
saturation 
 
(S
r
)
Degree 
of 
saturation 
(
S
r
) is the 
ratio, often expressed as 
a 
percentage, 
of 
the volume of 
water 
to the
volume of
 
voids:
 
 
 
 
 
 
 
 
 
Prove that                 
 
?
H
.
W
.
 
3.8 Unit weight 
is the 
weight 
of 
a 
soil 
per unit 
volume. The term 
bulk (total) unit 
weight (γ
t
) will 
be
devoted 
to unit
 
weight:
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
(
 
 
 
)
 
40
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
 
Special cases of unit
 
weight:
3.8.1 
Dry unit 
weight       
(
S
r  
=
 0):
 
 
 
For 
dry 
soil,            
, 
w=0% and              
. 
Then Equation 
3.13 
reduces
 
to
 
 
 
 
 
 
 
(
 
 
)
 
 
Then Equations 
3.13 
and 
3.15 
results
 
in
 
 
 
 
Derive      
if
 
V
s
=1.
H.
W.
 
3.8.2  Saturated unit weight           
(
S
r 
=
 
1):
 
 
 
  
 
 
 
 
 
(       
 
)
 
 
3.8.3  Submerged unit weight         
 
:
For unsaturated
 
soils
 
 
 
  
 
 
 
 
(
 
 
 
)
 
 
or
For saturated
 
soils
 
 
 
 
 
  
 
 
 
 
(       
 
)
 
 
The 
density 
of 
water                        and 
is 1000 
Kg/m
3  
= 1
 
g/cm
3
In 
t h e most 
applications 
it is not the mass that is important, but the 
force 
due to the mass, 
and  
the
weight, 
W, 
is 
related 
to the mass, 
M, 
by 
the
 
relation
 
e
 
=V
v
 
V
s
 
=1
 
V
 
Sol
i
d
s
 
V
o
i
ds
 
41
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
where 
g 
is the 
acceleration 
due to 
gravity. 
If 
M is 
measured 
in Kg 
and 
W 
in 
kN, g = 9.8 m/s
2
Note converting 
Kg
 
to
 
kN
:
 
W= 
M 
(
Kg) 
(9.8)/1000 
=
 
kN
3.9 Cohesive and cohesionless
 
soils
 
Cohesive soils: 
under dry 
or 
saturated 
or 
unsaturated conditions, grains 
of 
soils are stick together; a
force is required to separate
 
them.
 
Cohesionless soils: 
under 
dry or 
saturated conditions, grains 
of 
soils fall apart, whereas under
unsaturated conditions, the grains are stick together due 
to 
surface 
tension, see the 
next chapter (i. 
e.
suction).
 
 
Example
 
3.1:
A 
soil 
has an 
in-situ void 
ratio 
e
o
=1.87, w=60% 
and G
s
=2.75. 
What 
are the 
moist unit weight
and degree of 
saturation? Assume 
that
 
V
s
=1m
3
.
Solution:
 
42
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
Example
 
3.2
A 
soil 
has 
porosity 
of 
32.5%. For volume of 
1 cm
3
, how 
much water 
is 
required 
to 
saturate the
 
soil?
Solution:
 
43
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
Example
 
3.3
An 
airport runway 
fill 
needs 
600 
000 
m
3 
of 
soil 
compacted to a void 
ratio 
of 0.75. 
There 
are 
two
borrow 
pits 
A 
and 
B 
from where the required soil can 
be 
taken and transported to the site. Which 
of
the 
two borrow 
pits 
would be more
 
economical?
 
Solution
:
 
3.10 Additional
 
Problems
P3.1:
One cubic metre 
of 
wet 
soil weighs 19.80 
kN. 
If 
the 
specific 
gravity 
of 
soil particles 
is 
2.70 
and 
water
content 
is 
11%, 
find 
a) 
the 
void 
ratio, 
b) dry 
density and c) degree 
of
 
saturation.
 
P3.2:
 
A 
sample 
of clay 
taken 
from a 
natural stratum was 
found to be partially 
saturated and when tested 
in
the laboratory 
gave 
the following 
results. 
Compute the 
degree 
of
 
saturation.
 
Specific 
gravity of 
soil 
particles =
 
2.6;
wet weight 
of 
sample 
= 2.50
 
N;
dry 
weight 
of 
sample 
= 2.10 
N;
 
and
volume of 
sample= 
150
 
cm3.
 
P3.3:
The
 
mass
 
specific
 
gravity
 
of
 
a
 
fully
 
saturated
 
specimen
 
of
 
clay
 
having
 
a
 
water
 
content
 
of
 
30.5%
 
is
1.96. 
On oven drying, 
the mass 
specific 
gravity drops to 1.60. 
Calculate 
the 
specific 
gravity 
of
 
clay.
 
P3.4:
Aggregates 
from a material 
storage site 
are 
required 
for the 
embankment 
of a 
roadway. 
The porosity of
the 
aggregates at 
the 
storage site 
is 80%, 
and 
the 
desired 
porosity of the 
compacted aggregates 
in the
embankment 
is 20%. For a 
section 
of the embankment 7.6m 
wide 
x 
0.61m compacted thickness 
x
305m 
long, calculate 
the volume of 
aggregates
 
required.
 
P3.5:
An embankment 
for a highway is to be 
constructed from 
a 
soil 
compacted to a 
dry 
unit 
weight 
of
18kN/m
3
. The clay 
has 
to 
be 
trucked 
to the 
site 
from a borrow pit. The 
bulk 
unit 
weight 
of 
the soil in
the 
borrow 
pit is 17kN/m
3 
and 
its 
natural water content 
is 5%. 
Calculate 
the volume of clay 
from 
the
borrow 
pit 
required 
for 1 
cubic 
meter of 
embankment. 
The 
swell factor 
is 1.2 (20% 
free 
swell).
Assume G
s
=
 
2.7.
 
P3.6:
 
For an unsaturated 
(partially) 
soil deposit 
at 
a 
construction site, 
water 
content, 
w=15%, 
void 
ratio, e=0.6
and 
specific gravity 
of 
soil 
particles/solids, G
s
=2.67. Determine 
the
 
following
(a) degree 
of 
saturation, 
(b) dry unit 
weight, and 
(c) weight 
of 
water 
required 
to 
fully saturated 
5 
m
3
of
 
soil.
 
 
 
 
44
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
 
Answers
: 
(a)                      
, (b)                                
 
(c)
 
P3.7:
 
A 0.9m
3 
soil specimen 
weighs 
(1734693g) and has 
a 
water content 
of 
9%. 
The specific 
gravity of the
soil solids 
is 2.7. 
Calculate 
(1) 
γ
t
, 
(2) γ
d
, (3) 
e
, (4) 
n
, (5) 
V
w
, and (6) 
S
r 
(7) 
sat 
 
(8)
sub
Answers
:  
γ = 18.9 kN/m
3 
γ
d  
=17.33 
kN/m
3    
e =  0.528 ,  n 
=0.346, 
Vw= 0.143m
3 
, 
Sr =
 
45.9%
sat
= 
20.72   kN/m
3    , 
sub
= 
10.91 
 
kN/m
3
 
P3.8:
 
For 
a 
saturated soil, water content was 
40% 
and Gs was 
2.71. 
Determine 
the 
saturated and 
dry 
unit
weights.
Answers
: 
e =
 
1.084
 
,
 
,
 
P3.9: 
A 
sample 
of 
moist 
clay 
soil has 
e = 0.78, 
S
r
= 
0.93 
and G
s
=2.7. Determine 
the 
dry 
and 
wet unit
weights 
and 
water
 
content.
Answer: 
14.88kN/m
3
, 
18.88 
1kN/m
3 
and 
 
0.27
P3.10: 
A wet 
sample 
of 
sand 
directly above the 
water 
table 
was 
found 
to 
have 
a 
natural 
moisture
content 
of 15% 
and 
a unit 
weight 
of 18.84 
kN/m
3
. 
Laboratory 
tests on a 
dried sample indicated values
of 
e
min 
= 
0.50 
and 
e
max 
= 
0.85 for the 
densest and 
loosest 
states respectively. 
Compute the 
degree 
of
saturation and 
the 
relative density. Assume 
Gs 
=
 
2.65.
Answer
:  
S
r 
=  67.7%  ,  e = 0.587,  
Dr 
=
 
75.14%
P3.11: 
Diameter and height of a 
soil specimen are 
38mm 
and 
76mm 
respectively, 
in its 
natural
condition weighs 160.0g. 
When 
dried 
completely in 
an oven 
the 
specimen Weighs 
130.5 
g. 
The value
of Gs 
is
 
2.73.
What is the 
degree 
of saturation of the
 
specimen?
Answer:
 
77.12%
P3.12:  
For a 
soil, show
 
that
 
 
 
 
  
 
 
 
 
 
( 
 
)
 
45
 
Ahmed M. Hasan, PhD, Geotechnical Specialist, College 
of 
Engineering – Salahaddin
 
University-Erbil
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Soil consists of solids, liquids, and gases with voids in between. Water content, void ratio, porosity, specific gravity, mass specific gravity, degree of saturation, and unit weight are key parameters in characterizing soil behavior. Relationships between these properties are crucial for geotechnical analysis and design.

  • Soil Phase
  • Geotechnical
  • Water Content
  • Specific Gravity
  • Porosity

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  1. Chapter 3 3. Soil phase relationships Contents of chapter 3 1. Introduction 38 2. Watercontent(w) 39 3. Void ratio (e) 39 4. Porosity(n) 39 5. Specific gravity 40 6. Mass Specificgravity 40 7. Degreeof saturation 40 8. Unitweight 40 1. Dry unitweight 41 2. Saturated unit weight 41 3. Submergedunitweight 41 9. Cohesiveand cohesionless soils 42 10. AdditionalProblems 44 3.1Introduction Soil is composed of solids, liquids, and gases (see Figure 3.1a). The solid phase may be minerals, organic matter, or both. The spaces between the solids (soil particles) are called voids. Water is often the predominant liquid and air is the predominant gas. We will use the terms water and air instead of liquid and gas. The soil water is called pore water and plays a very important role in the behaviour of soils under load. If all the voids are filled by water, the soil is saturated. Otherwise, the soil is unsaturated. If all the voids are filled with air, the soil is said to be dry. 38 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  2. Figure 3.1 Soilphases We can idealize the three phases of soil, as shown in Figure 3.1b. The physical parameters of soils are influenced by the relative proportions of each of these phases. The total volume of the soil is the sum of the volume of solids (Vs), volume of water (Vw), and volume of air (Va); that is, where is the volume of voids. The weight of the soil is the sum of the weight of solids (ws) and the weight of water (ww). The weight of air is negligible. Thus, The following definitions have been established to describe the proportion of each constituent in a soil. Each equation can be presented with different variables. The most popular and convenient forms are given. You should try to memorize these relationships. 3.2 Water content (w) is the ratio, often expressed as a percentage, of the weight of water to the weight ofsolids: If organic matter is present in a soil, it may oxidize and decompose at 110 5 C 3.Void ratio (e) is the ratio of the volume of void space to the volume of solids. Void ratio is usually expressed as a decimal quantity: 0< e < 4.Porosity (n) is the ratio of the volume of voids to the total volume. Porosity is usually expressed as a percentage: 0< n <1 39 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  3. Porosity and void ratio are related by theexpressions Prove Equations 3.7 and 3.8 ? H.W 3.5 Specific gravity (Gs) is the ratio of the weight of the soil solids to the weight of water of equalvolume: 3.6 Mass Specific gravity (Gm) The Mass specific gravity of a soil may be defined as the ratio of mass or bulk unit weight of soil to the unit weight of water at the standard temperature (4 C). This is denoted by the letter symbol Gmand is givenby: 3.7 Degree of saturation (Sr) Degree of saturation (Sr) is the ratio, often expressed as a percentage, of the volume of water to the volume ofvoids: Prove that ? H.W. 3.8 Unit weight is the weight of a soil per unit volume. The term bulk (total) unit weight ( t) will be devoted to unit weight: ( ) 40 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  4. Special cases of unit weight: 3.8.1 Dry unit weight (Sr = 0): For dry soil, , w=0% and . Then Equation 3.13 reduces to ( ) Then Equations 3.13 and 3.15 results in Voids Derive if Vs=1. H.W. e=Vv V Solids Vs=1 3.8.2 Saturated unit weight (Sr =1): ( ) 3.8.3 Submerged unit weight : For unsaturatedsoils ( ) or For saturatedsoils ( ) The density of water and is 1000 Kg/m3 = 1 g/cm3 In t h e most applications it is not the mass that is important, but the force due to the mass, and the weight, W, is related to the mass, M, by therelation 41 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  5. where g g is the acceleration due to gravity. If M is measured in Kg and W in kN, g = 9.8 m/s2 Note converting Kg to kN: W= M (Kg) (9.8)/1000 = kN 3.9 Cohesive and cohesionless soils Cohesive soils: under dry or saturated or unsaturated conditions, grains of soils are stick together; a force is required to separate them. Cohesionless soils: under dry or saturated conditions, grains of soils fall apart, whereas under unsaturated conditions, the grains are stick together due to surface tension, see the next chapter (i. e. suction). Example3.1: A soil has an in-situ void ratio eo=1.87, w=60% and Gs=2.75. What are the moist unit weight and degree of saturation? Assume that Vs=1m3. Solution: 42 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  6. Example3.2 A soil has porosity of 32.5%. For volume of 1 cm3, how much water is required to saturate the soil? Solution: Example3.3 An airport runway fill needs 600 000 m3of soil compacted to a void ratio of 0.75. There are two borrow pits A and B from where the required soil can be taken and transported to the site. Which of the two borrowpits wouldbe moreeconomical? Borrowpit A B In situ voidratio 0.80 1.70 Transportationcost 5USD 2.5USD Solution: 43 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  7. 3.10 AdditionalProblems P3.1: One cubic metre of wet soil weighs 19.80 kN. If the specific gravity of soil particles is 2.70 and water content is 11%, find a) the void ratio, b) dry density and c) degree ofsaturation. P3.2: A sample of clay taken from a natural stratum was found to be partially saturated and when tested in the laboratory gave the following results. Compute the degree ofsaturation. Specific gravity of soil particles =2.6; wet weight of sample = 2.50 N; dry weight of sample = 2.10 N; and volume of sample= 150cm3. P3.3: The mass specific gravity of a fully saturated specimen of clay having a water content of 30.5% is 1.96. On oven drying, the mass specific gravity drops to 1.60. Calculate the specific gravity of clay. P3.4: Aggregates from a material storage site are required for the embankment of a roadway. The porosity of the aggregates at the storage site is 80%, and the desired porosity of the compacted aggregates in the embankment is 20%. For a section of the embankment 7.6m wide x 0.61m compacted thickness x 305m long, calculate the volume of aggregates required. P3.5: An embankment for a highway is to be constructed from a soil compacted to a dry unit weight of 18kN/m3. The clay has to be trucked to the site from a borrow pit. The bulk unit weight of the soil in the borrow pit is 17kN/m3and its natural water content is 5%. Calculate the volume of clay from the borrow pit required for 1 cubic meter of embankment. The swell factor is 1.2 (20% free swell). Assume Gs=2.7. P3.6: For an unsaturated (partially) soil deposit at a construction site, water content, w=15%, void ratio, e=0.6 and specific gravity of soil particles/solids, Gs=2.67. Determine the following (a) degree of saturation, (b) dry unit weight, and (c) weight of water required to fully saturated 5 m3 ofsoil. Answers: (a) , (b) (c) 44 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

  8. P3.7: A 0.9m3 soil specimen weighs (1734693g) and has a water content of 9%. The specific gravity of the soil solids is 2.7. Calculate (1) t, (2) d, (3) e, (4) n, (5) Vw, and (6) Sr (7) sat (8) sub Answers: = 18.9 kN/m3 d =17.33 kN/m3 e = 0.528 , n =0.346, Vw= 0.143m3 , Sr = 45.9% sat= 20.72 kN/m3 , sub= 10.91 kN/m3 P3.8: For a saturated soil, water content was 40% and Gs was 2.71. Determine the saturated and dry unit weights. Answers: e = 1.084 , , P3.9: A sample of moist clay soil has e = 0.78, Sr= 0.93 and Gs=2.7. Determine the dry and wet unit weights and water content. Answer: 14.88kN/m3, 18.88 1kN/m3and 0.27 P3.10: A wet sample of sand directly above the water table was found to have a natural moisture content of 15% and a unit weight of 18.84 kN/m3. Laboratory tests on a dried sample indicated values of emin= 0.50 and emax= 0.85 for the densest and loosest states respectively. Compute the degree of saturation and the relative density.Assume Gs = 2.65. Answer: Sr= 67.7% , e = 0.587, Dr =75.14% P3.11: Diameter and height of a soil specimen are 38mm and 76mm respectively, in its natural condition weighs 160.0g. When dried completely in an oven the specimen Weighs 130.5 g. The value of Gs is 2.73. What is the degree of saturation of thespecimen? Answer:77.12% P3.12: For a soil, show that ( ) 45 Ahmed M. Hasan, PhD, Geotechnical Specialist, College of Engineering Salahaddin University-Erbil

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