Sierpiński‘s Theorem
Delve into the intricacies of Second-Order Zermelo-Fraenkel Set Theory as it explores fundamental concepts such as extensionality, empty sets, foundation, unions, and power sets. Dive deeper into cardinality, product notations, the Axiom of Choice, and more.
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First Master Seminar Talk Sierpi ski s Theorem The generalized continuum hypothesis implies the axiom of choice Felix Rech Advisor: Dominik Kirst June 14, 2019
Second-Order Zermelo-Fraenkel Set Theory [Kirst and Smolka 2017] Assume a type ??? and a relation _ _ ??? ??? ????. Extensionality Sets are equal if they have the same elements. Empty Set There is an empty set. Foundation The element relation is well-founded. Union For a given set, we can build the union of all elements. Power Set Every set has a power set. The numerals form a set. Infinity Replacement The image of a set under a functional relation is a set. 2
Empty Set There is an empty set. Foundation The element relation is well-founded. ? ?. accessible(?) accessible(?) _ _ is well-founded if all sets are accessible. 3
Second-Order Zermelo-Fraenkel Set Theory [Kirst and Smolka 2017] Assume a type ??? and a relation _ _ ??? ??? ????. Extensionality Sets are equal if they have the same elements. Empty Set There is an empty set. Foundation The element relation is well-founded. Union For a given set, we can build the union of all elements. Power Set Every set has a power set. The numerals form a set. Infinity Replacement The image of a set under a functional relation is a set. 4
Power Set Every set has a power set. Infinity The numerals form a set. Successor ? ? ? ? Numerals 0 ? + 1 ?( ?) ? ?.? = ? 5 Replacement The image of a set under a functional relation is a set.
Second-Order Zermelo-Fraenkel Set Theory [Kirst and Smolka 2017] Assume a type ??? and a relation _ _ ??? ??? ????. Extensionality Sets are equal if they have the same elements. Empty Set There is an empty set. Foundation The element relation is well-founded. Union For a given set, we can build the union of all elements. Power Set Every set has a power set. The numerals form a set. Infinity Replacement The image of a set under a functional relation is a set. ??? ??? ???? 6
Notations Cardinality Product ? ? there is a bijection ? ? ?,? ? , ?,? ? ? there is an injection ? ? ? ? ?,? ? ?,? ? Disjoint Union Infinity ? + ? 0,? ? ? ? is infinite ? 1,? ? ? 7
Axiom of Choice ? ??? ? ? ???. Fix and ?.?(?) ?.? ? 8
Axiom of Choice ? ??? ? ? ???. Fix and ?.inhabited(?(?)) ?.? ? 9
Axiom of Choice ? ??? ? ? ???. Fix and ?.inhabited(?(?)) inhabited( ?.? ? ) 10
Consequences of the Axiom of Choice Every surjection has a right inverse. Every non-listable set ? satisfies ?. Every infinite set ? has a bijection ? ? ?. Linearity: ? ? or ? ? for all sets ? and ?. 11
Continuum Hypothesis ? ?( ) ? ? ?( ) 12
Generalized Continuum Hypothesis A infinite ? ? ?(?) ? ? ? ?(?) 13
Ordinals Representatives for isomorphism classes of well-orders Definition. A set ? is transitive if ? ? ? ? ? ?. We define the class ? of ordinals inductively: ? is transitive ? ?. ? ? ? ? ?2 , ? = { , ? , , , ? , } 14
Ordinals are Representatives Every ordinal is well-ordered by the -relation. Isomorphic ordinals are equal: ? ? ? = ?. Every well-ordered set has a unique isomorphic ordinal. 15
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?4(?) 2. ?is an ordinal 3. ? ? 16
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?4(?) 2. ?is an ordinal 3. ? ? Assume ? ?. ? ?? 17
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?4(?) 2. ?is an ordinal Elements are ordinals. Transitivity: 18 3.
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?4(?) 2. ?is an ordinal Elements are ordinals. Transitivity: Assume ? ? ? ? and ? ?. Assume ? ? ? ? and ? ? ?. ? ? 19 3.
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?4(?) 1. ? ?4(?) 20
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?2? ? ?4(?) ?,? = ? , ?,? ? ? ?2? 21
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?2? ? ?4(?) ?,? = ? , ?,? ? ? ?2? 22
Hartogs Number [1915] A big ordinal ? ? ? ? ? ?2? ? ?4(?) 1. f ? ?,? = ? , ?,? ? ? ? ? ? ? ? ? ? ? ?2? 23
Hartogs Number [1915] A big ordinal ? ? ? ? ? ?2? ? ?4(?) 1. f ? ?,? = ? , ?,? ? ? ? ? ? ? ? ? ? ? ?2? Injectivity: Assume ? ? = ?(?) ? ? ? ? = ? 24
Hartogs Number [1915] A big ordinal ? ? ? ? ? 1. ? ?4(?) 2. ?is an ordinal 3. ? ? 25
Sierpiskis Theorem [1947] Generalized continuum hypothesis Axiom of choice 26
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice 27
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice 28
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) 29
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ?3(?) ?4(?) ? 30
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ?3(?) ?3? + ? ?4(?) 31
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ?4? ? ?3(?) ?3? + ? ?4(?) < 32
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ?4? ? ?3(?) ?3? + ? ?4(?) < 33
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ? ?3(?) ?4? ? ?3(?) ?3? + ? ?4(?) < 34
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ? ?3(?) ?4? ? ?2(?) ?2? + ? ?3(?) 35
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ? ?3(?) ?4? ? ?3? ? ?2(?) ?2? + ? ?3(?) < 36
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ? ?3(?) ?4? ? ? ?2(?) ?3? ? ?2(?) ?2? + ? ?3(?) < 37
Sierpiskis Theorem [1947] Generalized continuum hypothesis Well-ordering theorem Axiom of choice Fix a set ? (w.l.o.g. large enough). We show ? ?. ? ?4(?) ? ?3(?) ?4? ? ? ?2(?) ?3? ? ?2? ? ? ?(?) ? ? ? ? ? ? 38
Sets as Types Existing Class _ _ . Coercion ???????_?? ? ??? ? ??? ? ? . ? ? stands for ? ??? ? ? ? ??? ? ? 39
Advantages of Sets as Types Reusable Definitions and Notations ? ? ?,? ? ? ? ? ? ? ? ? ?????????? ? (? ?) ? ????? (? ?) Tracking and Checking of Types ?1 {?,? ???}.? ? ? ? ? is even ? Valid ?1 , Not valid ?1 40
Problems with Sets as Types is not valid. element ? ? = ? element ? = element ? 41
Eliminators on Sets Inspired by recursion schemes in Coq: numeral_rec ? ???.? ? ? ? Not into arbitrary types! 42
Conclusion 1. Higher-order axiomatisation of set theory 2. Hartogs number as a big ordinal ( ? ?) 3. Sierpi ski s theorem: Under GCH, the Hartogs number is big enough. ( ? ?) 4. Main result formalized in Coq (XM + FE) Thank you! Next Goals Type-theoretic version of Sierpi ski s theorem Consistency of the axiom of choice by exhibiting the constructible hierarchy ? 43
References Dominik Kirst and Gert Smolka. Categoricity results for second-order ZF in dependent type theory. International Conference on Interactive Theorem Proving. Springer, Cham, 2017. Friedrich Hartogs. ber das Problem der Wohlordnung. Mathematische Annalen 76.4 (1915): 438-443. Wac aw Sierpi ski. L'hypoth se g n ralis e du continu et l'axiome du choix. Fundamenta Mathematicae 1.34 (1947): 1-5. 44