Hydraulic Cylinders and Their Applications

 
Lecture
 
5
Cylinders
Cylinders 
are 
linear actuators whose 
output 
force or motion 
is 
in 
a
straight 
line. 
Their function 
is to 
convert 
hydraulic power into linear
mechanical power. Hydraulic cylinders extend and retract 
to 
perform a
complete cycle of operation.
 
Their 
work applications 
may 
include pulling, pushing, 
and 
pressing. 
The
type 
of 
cylinder to 
be 
used 
along 
with 
its design 
is based 
on 
a specific
application. 
The 
simplest of linear actuators 
is 
a 
ram 
which 
is 
shown 
in
Figure 1. 
It 
has 
only 
one 
fluid 
chamber and exerts force 
in 
one 
direction
only. 
Rams 
are 
widely 
used 
in 
applications 
where 
stability 
is 
needed on
heavy loads. 
Ram-type cylinders 
are 
practical 
for 
long strokes and 
are
used 
on 
jacks, elevators and automobile
 
hoists.
 
Figure 
1: 
Hydraulic
 
ram
 
Hydraulic 
cylinders 
are 
further classified
 
as:
Single 
acting 
cylinders
 
and
Double acting
 
cylinders
 
Single acting 
cylinder
Single 
acting cylinders 
are 
pressurized at 
one 
end only while 
the  opposite
end  
is  vented  to  the  
atmosphere  or  
tank.  
They  
are 
 
usually
designed 
in 
such 
a way that a 
device 
such 
as 
an 
internal spring retracts
them.  Figure  
2  
is  
an 
illustration of 
the  
simplest 
form 
of a 
 
single  
acting
hydraulic 
cylinder along with its symbolic
 
representation.
 
23
 
A 
single 
acting hydraulic cylinder 
consists 
of 
a piston inside a cylindrical
housing 
called a 
barrel. 
Attached 
to one 
end 
of 
the 
piston 
is 
a rod, which
extends 
outside 
one end 
of 
the 
cylinder 
(rod 
end). At 
the 
other end
(blank 
end) is 
a port for 
the 
entrance and exit of
 
oil.
 
Figure 
2: 
Single acting hydraulic
 
cylinder
 
Double 
acting
 
cylinder
Double   
acting   cylinders   
are   the   
most  commonly   
used   
cylinders
 
in
hydraulic 
applications. 
Here 
pressure can 
be 
applied 
to 
either 
port giving
power 
in 
both directions. Figure 3 shows 
the 
typical construction of a
double  
acting cylinder.  
The  
cylinder consists of 
five  basic
 
parts: 
two 
end
 
Blind
 
end
 
Piston
 
24
 
D
ra
i
n
 
caps (a 
base 
cap 
and 
a bearing cap) with 
port 
connections, a cylinder
barrel, 
a piston and 
the rod 
itself. 
This 
basic construction 
provides 
for
simple manufacture 
as 
the 
end caps and 
pistons 
remain 
the 
same 
for
different lengths of 
the 
same 
diameter cylinder. The end 
caps 
can 
be
secured to the 
barrel 
by 
welding, through tie rods or 
by 
threaded
connections.
 
25
 
Figure 
3: 
Construction 
of 
a double acting
 
cylinder
A 
hydraulic 
cylinder 
is used to 
compress a 
car 
body down 
to 
a 
bale 
size in
10 
s. 
The 
operation requires a 
10 
ft 
stroke 
(S) 
and 
a force (Pbad) of 8000
lb. 
If 
a 1000 
psi
 
pressure
(P)
pump is 
selected,
 
find
(a)
The 
required piston
 
area
(b)
The 
necessary pump 
flow
 
rate
(c)
The 
hydraulic horsepower delivered 
by the
 
cylinder
 
Solution:
Here
 
F
load
 
is
 
the
 
force
 
required
 
to
 
crush
 
the
 
car
 
for
 
which
 
the
 
pump
 
used
can deliver a pressure of 1000 
psi. 
So, to 
get 
the 
area 
of 
the 
piston
required 
to 
take 
this
 
load,
(a)
Force = P
 
xA
so
P= 
F
load 
/A= 
8000/1000
= 8
 
sq.in.
(b)
The 
volumetric displacement of 
the 
cylinder 
equals 
the 
fluid volume
swept 
by the 
cylinder 
during its 
stroke length 
(5) 
while 
the required
pump 
flow 
rate equals the volumetric 
displacement divided 
by 
the 
time
required for 
the 
stroke.
 
So,
G(ftVs) = 
(AxS)/t= 
((8/144)
 
X10)
/
10
= 0.056 
ft
3
 
/s
1 ft
3
/s = 
448
 
gpm
So
 
26
 
27
 
=
 
448x0.056
= 25.1
 
gpm
In order 
to 
calculate 
the power 
delivered 
we 
will use the 
equation
H
p
=[P(psi)xQ(gpm)]/1714
This 
has been 
derived 
by 
using the 
conversion factors, 
keeping in
 
view
the
 
basic
Power-energy equation which 
is
Power
 
=Energy/Time
So
Hp 
=
 
(1000x25.1)/1714
=
 
14.6hp
 
This 
is the 
theoretical horsepower delivered 
by 
the 
cylinder assuming its
efficiency 
to 
be 
100%. 
Then, 
to calculate 
the 
actual 
hp, this 
should 
be
multiplied by 
the 
efficiency 
specified 
by 
the
 
manufacturer.
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Cylinders are linear actuators converting hydraulic power into mechanical power for pulling, pushing, and pressing tasks. They can be single-acting or double-acting, with specific designs for different applications. Ram-type cylinders offer stability for heavy loads, and double-acting cylinders are versatile for applications requiring power in both directions. Learn about the construction, components, and calculations involved in hydraulic cylinders' operation and use.

  • Hydraulic Cylinders
  • Linear Actuators
  • Ram-Type
  • Double-Acting
  • Applications

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  1. Lecture5 Cylinders Cylinders are linear actuators whose output force or motion is in a straight line. Their function is to convert hydraulic power into linear mechanical power. Hydraulic cylinders extend and retract to perform a completecycle of operation. Their work applications may include pulling, pushing, and pressing. The type of cylinder to be used along with its design is based on a specific application. The simplest of linear actuators is a ram which is shown in Figure 1. It has only one fluid chamber and exerts force in one direction only. Rams are widely used in applications where stability is needed on heavy loads. Ram-type cylinders are practical for long strokes and are used on jacks, elevatorsand automobilehoists. Figure 1: Hydraulicram Hydraulic cylinders are further classifiedas: Single acting cylindersand Double acting cylinders Single acting cylinder Single acting cylinders are pressurized at one end only while the opposite end is vented to the atmosphere or tank. They are usually designed in such a way that a device such as an internal spring retracts them. Figure 2 is an illustration of the simplest form of a single acting hydraulic cylinder along with its symbolic representation. 23

  2. A single acting hydraulic cylinder consists of a piston inside a cylindrical housing called a barrel. Attached to one end of the piston is a rod, which extends outside one end of the cylinder (rod end). At the other end (blank end) is a port for the entrance and exit of oil. Blindend Piston Drain Figure 2: Single acting hydraulic cylinder Double acting cylinder Double acting cylinders are the most commonly used cylinders in hydraulic applications. Here pressure can be applied to either port giving power in both directions. Figure 3 shows the typical construction of a double acting cylinder. The cylinder consistsoffive basicparts: two end 24

  3. caps (a base cap and a bearing cap) with port connections, a cylinder barrel, a piston and the rod itself. This basic construction provides for simple manufacture as the end caps and pistons remain the same for different lengths of the same diameter cylinder. The end caps can be secured to the barrel by welding, through tie rods or by threaded connections. 25

  4. Figure 3: Construction of a double actingcylinder A hydraulic cylinder is used to compress a car body down to a bale size in 10 s. The operation requires a 10 ft stroke (S) and a force (Pbad) of 8000 lb. If a 1000 psi pressure (P) pump is selected, find (a) The required piston area (b) The necessary pump flow rate (c) The hydraulic horsepower delivered by the cylinder Solution: Here Fload is the force required to crush the car for which the pump used can deliver a pressure of 1000 psi. So, to get the area of the piston required to take this load, (a)Force = PxA so P= Fload /A= 8000/1000= 8sq.in. (b)The volumetric displacement of the cylinder equals the fluid volume swept by the cylinder during its stroke length (5) while the required pump flow rate equals the volumetric displacement divided by the time required forthe stroke. So, G(ftVs) = (AxS)/t= ((8/144) X10)/10 = 0.056 ft3/s 1 ft3/s = 448gpm So 26

  5. = 448x0.056 = 25.1gpm In order to calculate the power delivered we will use the equation Hp=[P(psi)xQ(gpm)]/1714 This has been derived by using the conversion factors, keeping in view the basic Power-energy equation which is Power =Energy/Time So Hp = (1000x25.1)/1714 = 14.6hp This is the theoretical horsepower delivered by the cylinder assuming its efficiency to be 100%. Then, to calculate the actual hp, this should be multiplied by the efficiencyspecified by the manufacturer. 27

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