Groundwater Hydrology Concepts at Brigham Young University
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CE 547 – BRIGHAM YOUNG UNIVERSITY
Understand the derivation of the transient
term of the governing equation
Understand the physical mechanisms behind
specific storage
Understand the difference between specific
storage, storativity, and specific yield
inflow - outflow = 0
mass flow rate =
v
Assume that we have no sources and sinks.
The term:
represents the change in mass stored in the
system.
The mass per unit volume can be expressed as the
density times the volume of the voids:
m =
V
v
The change in storage with respect to time can then
be represented as:
=
(n V
total
)
=
n dx dy dz
In the steady state case:
inflow - outflow = 0
or:
Now we have:
or:
which reduces to:
Once again, if
is constant:
Assuming k
xy
= k
xz
= k
yz
= 0 and inserting
Darcy's law:
Now we need to simplify
n/
t
and write it in terms of head
since the left hand side of the equation is expressed in terms of
head.
The term
n/
t
represents the change in volume due to a
change in the head (n changes due to a change in head).
The
term can be related to head as follows:
where
or the change in water volume stored in a unit volume of the
aquifer per unit change in head.
1
1
1
Specific
Storage
Change in water
volume stored in
a unit volume of
the aquifer per
unit change in
head.
Substituting:
This is sometimes called the "diffusion
equation". Note that now we have an
expression relating head (h) to
position (x, y, z) and time (t).
If we have sources or sinks we can simply add one more
term, R, which is intrinsically positive and represents
inflow to the system.
or
An expression for specific storage can be derived as
follows: A decrease in the head infers a decrease in the
fluid pore pressure u and an increase in the effective
stress in the soil (
‘). The water that is released from the
aquifer due to a decrease in h is due to:
dV
w
= - dV
T
=
V
T
d
'
(1) Compression of the aquifer due to an increase in
'.
This is controlled by the aquifer compressibility,
.
for a unit volume of the aquifer, V
T
= 1, and
dV
w
=
d
'
d
' = - du = -
w
dh
substituting:
dV
w
= -
w
dh
for a unit change in head, dh = -1:
dVw
=
w
(2) Expansion of the pore water due to a decrease in u. This
is controlled by the fluid compressibility,
:
dV
w
= -
V
w
du
since V
w
= nV
T
, = n (for unit volume of aquifer)
dV
w
= -
n du
Also, for a unit drop in head (dh = -1):
du =
w
dh = -
w
thus:
dV
w
=
n
w
Combining both terms gives us an expression for
specific storage:
S
s
=
w
(
+ n
)
Note:
where:
= strain
E = Modulus of elasticity
decreases with increasing stiffness and typical values
are given below (Freeze and Cherry):
is a constant for water equal to
4.4 X 10
-10
m
2
/N
Explore the derivation of transient terms, specific storage mechanisms, and distinctions between specific storage, storativity, and specific yield in groundwater hydrology. Delve into the mathematical equations governing groundwater flow and storage, understanding the change in mass stored in the system and its relation to volume and head. Discover how specific storage relates to changes in water volume stored per unit change in head.
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Presentation Transcript
Understand the derivation of the transient term of the governing equation Understand the physical mechanisms behind specific storage Understand the difference between specific storage, storativity, and specific yield
y z inflow - outflow = 0 ( v ) dz ( = ( v ) v ) - in dx x ( v x) x out x in x mass flow rate = v dy x dx 2 2 2 h 2 h 2 h 2 + + = k k k 0 x y z x y z
storage = + inf low outflow sources , sin ks t Assume that we have no sources and sinks. The term: storage t represents the change in mass stored in the system.
The mass per unit volume can be expressed as the density times the volume of the voids: m = Vv = (n Vtotal) = n dx dy dz The change in storage with respect to time can then be represented as: ( )dxdydz n t
In the steady state case: inflow - outflow = 0 or: ( ) ( ) ( ) v v v y = dxdydz dxdydz dxdydz 0 x z x y z
Now we have: inflow outflow = storage t or: dxdydz ? vy ? vx dxdydz ? vz dxdydz ?x ?y ?z =? n dxdydz ?t which reduces to: ? vy ? vx ? vz =? n ?x ?y ?z ?t
Once again, if is constant: v n v v y = x z x y z t Assuming kxy= kxz= kyz= 0 and inserting Darcy's law: 2 2 2 h 2 h 2 h 2 n + + = k k k x y z x y z t
Now we need to simplify n/t and write it in terms of head since the left hand side of the equation is expressed in terms of head. The term n/ t represents the change in volume due to a change in the head (n changes due to a change in head). The term can be related to head as follows: n h = S s t t where dV = = S Specific storage w s dh or the change in water volume stored in a unit volume of the aquifer per unit change in head.
1 Change in water volume stored in a unit volume of the aquifer per unit change in head. Specific Storage 1 1 1
Substituting: 2 2 2 h 2 h 2 h 2 h + + = k k k S x y z s x y z t This is sometimes called the "diffusion equation". Note that now we have an expression relating head (h) to position (x, y, z) and time (t).
If we have sources or sinks we can simply add one more term, R, which is intrinsically positive and represents inflow to the system. 2 2 2 h 2 h 2 h 2 h + + + = k k k R S x y z s x y z t or 2 2 2 h 2 h 2 h 2 h + + = k k k S R x y z s x y z t
An expression for specific storage can be derived as follows: A decrease in the head infers a decrease in the fluid pore pressure u and an increase in the effective stress in the soil ( ). The water that is released from the aquifer due to a decrease in h is due to: (1) Compression of the aquifer due to an increase in '. This is controlled by the aquifer compressibility, . dVw = - dVT = VT d '
for a unit volume of the aquifer, VT = 1, and dVw = d ' d ' = - du = - wdh substituting: dVw = - w dh for a unit change in head, dh = -1: dVw = w
(2) Expansion of the pore water due to a decrease in u. This is controlled by the fluid compressibility, : dVw = - Vw du since Vw = nVT, = n (for unit volume of aquifer) dVw = - n du Also, for a unit drop in head (dh = -1): du = w dh = - w thus: dVw = n w
Combining both terms gives us an expression for specific storage: Ss = w( + n ) Note: 1 = = E ' where: = strain E = Modulus of elasticity
decreases with increasing stiffness and typical values are given below (Freeze and Cherry): (m2 / N) Media Clay 10-6 - 10-8 Sand 10-7 - 10-9 Gravel 10-8 - 10-10 Jointed Rock 10-8 - 10-10 Sound Rock 10-9 - 10-11 is a constant for water equal to 4.4 X 10-10 m2/N
