Geometry Concepts and Postulates

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Section 2.2
 
Structure of Geometry
 
Definitions
 
Postulate(axiom)
- is a statement
accepted without proof
 
Theorem
-is a statement that is
proven by using defs, postulates, or
previously proven theorems
 
Postulates:
 
Ruler Postulate-  
the pts on a # line
can be paired 1:1 with the set of reals
#’s(coords) and the distance between
any
    2 pts = 
diff of their coords 
 
Ex:   A                B
        -6               4
 
d AB= 
-6 – 4 
= 10 units
 
Example :
 
Find the distance from A to B:
                    A                B
                    3                8
AB =         
8 – 3 
= 5
 
 
 
Segment Addition Postulate-
 
Pts A, B, & C are collinear and B is in between
A & C, then AB + BC = AC   ( 2parts sum= whole)
 
If B is between A and C, then AB + BC = AC
             A                  B            C
 
S is between T and V.  R is between S and T.
T is between R and Q.  QV = 18, QT= 6,
TR=RS=SV.  Make a sketch and answer.
 
Find
 
1. RS
   
2. QS
 
 
3. TS
   
4. TV
 
 
Suppose J is between H and K.  Use
the segment Addition Postulate to
solve for x.  Then find the length of
each segment.
1. HJ =  2x + 4
   
2. HJ = 5x -3
    JK = 3x + 3
    
JK = 8x - 9
 
KH = 22
     
KH = 131
3. HJ = 2x + 1/3
 
JK = 5x + 2/3
 
KH = 12x - 4
 
 
 
Protractor Postulate- 
the rays of a given
angle can be paired 1:1 on the protractor
and the measure is determined by:
 
  
diffs of those real #’s
 
 
Angle addition Postulate-
 
If C is in the interior of <AOD, then
 
m<AOC + m<COD = m<AOD.
 
 
 
Q is in the interior of <ROS.  S is in the
interior of <QOP.  P is in the interior of <SOT.
S is in the interior of <ROT and m<ROT= 160°.
M<SOT = 100° and m<ROQ = m<QOS = m<POT.
Make a sketch and answer the following:
 
1. find m<QOP
 
  2. m<QOT
  
3. m<ROQ
 
 
Let Q be in the interior of <POR.
Use the angle addition Postulate to
solve for x.  Find the measure of
each angle.
1. m<POQ = (X + 4)°
 
  2. m<POQ = (3x + 7)°
    m<QOR = (2x – 2)°
 
  
 
 m<QOR = (5x – 2)°
 
m<POR = 26°
    
 m<POR = 61°
 
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Explore key concepts in geometry including definitions of postulates and theorems, the Segment Addition Postulate, and the Protractor Postulate. Learn how to apply these principles to solve problems and determine lengths and angles within geometric figures.

  • Geometry
  • Postulates
  • Theorems
  • Segments
  • Angles

Uploaded on Sep 23, 2024 | 0 Views


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  1. Section 2.2 Structure of Geometry

  2. Definitions Postulate(axiom)- is a statement accepted without proof Theorem-is a statement that is proven by using defs, postulates, or previously proven theorems

  3. Postulates: Ruler Postulate- the pts on a # line can be paired 1:1 with the set of reals # s(coords) and the distance between any 2 pts = diff of their coords Ex: A B -6 4 d AB= -6 4 = 10 units

  4. Example : Find the distance from A to B: A B 3 8 AB = 8 3 = 5

  5. Segment Addition Postulate- Pts A, B, & C are collinear and B is in between A & C, then AB + BC = AC ( 2parts sum= whole) If B is between A and C, then AB + BC = AC A B C

  6. S is between T and V. R is between S and T. T is between R and Q. QV = 18, QT= 6, TR=RS=SV. Make a sketch and answer. Find 1. RS 2. QS 3. TS 4. TV

  7. Suppose J is between H and K. Use the segment Addition Postulate to solve for x. Then find the length of each segment. 1. HJ = 2x + 4 JK = 3x + 3 KH = 22 2. HJ = 5x -3 JK = 8x - 9 KH = 131 3. HJ = 2x + 1/3 JK = 5x + 2/3 KH = 12x - 4

  8. Protractor Postulate- the rays of a given angle can be paired 1:1 on the protractor and the measure is determined by: diffs of those real # s

  9. Angle addition Postulate- If C is in the interior of <AOD, then m<AOC + m<COD = m<AOD.

  10. Q is in the interior of <ROS. S is in the interior of <QOP. P is in the interior of <SOT. S is in the interior of <ROT and m<ROT= 160 . M<SOT = 100 and m<ROQ = m<QOS = m<POT. Make a sketch and answer the following: 1. find m<QOP 2. m<QOT 3. m<ROQ

  11. Let Q be in the interior of <POR. Use the angle addition Postulate to solve for x. Find the measure of each angle. 1. m<POQ = (X + 4) m<QOR = (2x 2) m<POR = 26 2. m<POQ = (3x + 7) m<QOR = (5x 2) m<POR = 61

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