Exploring Vectors: Magnitude, Direction, and Operations

 
Vectors
(Knight: 3.1 to 3.4)
 
Scalars and Vectors
 
    
Temperature
 = Scalar
Quantity is specified by a single
number giving its 
magnitude
.
 
     
Velocity
 = Vector
Quantity is specified by
 three numbers that give
its 
magnitude
 and 
direction
(or its components in three
perpendicular directions).
Properties of Vectors
 
Two vectors are equal if they have the same magnitude and direction.
Adding Vectors
Subtracting Vectors
Combining Vectors
Using the Tip-to-Tail Rule
 
Clicker Question 1
 
Question:
  Which vector shows the sum of
A
1
 + A
2
 + A
3 
?
Multiplication by a Scalar
 
Determining the Components of a Vector
1.
The absolute value 
|
A
x
|
 of the x-component 
A
x
 is the
magnitude of the component vector     .
2.
The 
sign
 of 
A
x
 
is positive if     points in the positive x-direction,
negative if     points in the negative x-direction.
3.
The y- and z-components, 
A
y
 and 
A
z
, are determined similarly.
Coordinate Systems
and Vector Components
 
 
Knight’s Terminology:
 The “x-component” 
A
x
 is a 
scalar
.
 The “component vector”      is a
vector
 that always points along the
 x axis.
 The “vector” is      , and it can
point in 
any
 direction.
Determining Components
Cartesian and Polar
Coordinate Representations
Unit Vectors
 
Example:
A
 
 
= 100 i m
= 100 i m
B
 
 
= (
= (
200 Cos 45
200 Cos 45
0
0
 i + 200 Cos 45
 i + 200 Cos 45
0
0
 j 
) m
) m
    = (
    = (
141 i + 141
141 i + 141
 j 
) m
) m
Working with Vectors
 
C
 = 
A
 + 
B
   = (
100 i m) + (-141 i + 141
100 i m) + (-141 i + 141
 j 
) m
) m
   = (-41 i + 141
   = (-41 i + 141
 j 
) m
) m
 
^
^
^
^
^
^
 
^
 
^
 
^
 
C = [C
x
2
 + C
y
2
]
½
 = [
(-41 m)
(-41 m)
2
2
 + (141
 + (141
 m
)
)
2
2
]
½
 = 147 m
 = Tan
-1
[C
y
/|C
x
|] = Tan
-1
[141/41] = 74
0
 
Note:
  Tan
-1
 
 ATan = arc-tangent = the angle whose tangent is …
 
Tilted Axes
 
C
x 
= C Cos 
C
y
 = C Sin 
Arbitrary Directions
 
Perpendicular to a Surface
 
Chapter 3 Summary (1)
 
Chapter 3 Summary (2)
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Delve into the world of vectors, understanding their properties, how to add and subtract them, and determining their components in different coordinate systems. Learn about scalar quantities, vector quantities, the tip-to-tail rule, and the role of unit vectors in calculations.

  • Vectors
  • Vector Operations
  • Coordinate Systems
  • Scalar Quantities
  • Unit Vectors

Uploaded on Aug 10, 2024 | 0 Views


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  1. Vectors (Knight: 3.1 to 3.4)

  2. Scalars and Vectors Temperature = Scalar Quantity is specified by a single number giving its magnitude. Velocity = Vector Quantity is specified by three numbers that give its magnitude and direction (or its components in three perpendicular directions).

  3. Properties of Vectors Two vectors are equal if they have the same magnitude and direction.

  4. Adding Vectors

  5. Subtracting Vectors

  6. Combining Vectors

  7. Using the Tip-to-Tail Rule

  8. Clicker Question 1 Question: Which vector shows the sum of A1 + A2 + A3 ?

  9. Multiplication by a Scalar

  10. Coordinate Systems and Vector Components Determining the Components of a Vector 1. The absolute value |Ax| of the x-component Ax is the magnitude of the component vector . 2. The sign of Axis positive if points in the positive x-direction, negative if points in the negative x-direction. 3. The y- and z-components, Ay and Az, are determined similarly. xA x A x A Knight s Terminology: The x-component Ax is a scalar. The component vector is a vector that always points along the x axis. x A The vector is , and it can point in any direction. A

  11. Determining Components

  12. Cartesian and Polar Coordinate Representations

  13. Unit Vectors i = = = = (1,0,0) unit vector in +x-direction = "i-hat" j (0,1,0) unit vector in +x-direction = "j-hat" = = (0,0,1) unit vector in +z-direction = "k-hat" k = + + = + + = ( , , ) A A A A A i A j A k A A A x y k x y z x y z Example: i j = + = (4, 2,5) 4 2 5 B k

  14. Working with Vectors ^ A = 100 i m B = ( 200 Cos 450 i + 200 Cos 450 j ) m = ( 141 i + 141 j ) m ^ ^ ^ ^ C = A + B = (100 i m) + (-141 i + 141 j ) m = (-41 i + 141 j ) m ^ ^ ^ ^ C = [Cx2 + Cy2] = [(-41 m)2 + (141 m)2] = 147 m = Tan-1[Cy/|Cx|] = Tan-1[141/41] = 740 Note: Tan-1 ATan = arc-tangent = the angle whose tangent is

  15. Tilted Axes Cx = C Cos Cy = C Sin

  16. Arbitrary Directions

  17. Perpendicular to a Surface

  18. Chapter 3 Summary (1)

  19. Chapter 3 Summary (2)

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