Exploring Vectors: Magnitude, Direction, and Operations

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Delve into the world of vectors, understanding their properties, how to add and subtract them, and determining their components in different coordinate systems. Learn about scalar quantities, vector quantities, the tip-to-tail rule, and the role of unit vectors in calculations.


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  1. Vectors (Knight: 3.1 to 3.4)

  2. Scalars and Vectors Temperature = Scalar Quantity is specified by a single number giving its magnitude. Velocity = Vector Quantity is specified by three numbers that give its magnitude and direction (or its components in three perpendicular directions).

  3. Properties of Vectors Two vectors are equal if they have the same magnitude and direction.

  4. Adding Vectors

  5. Subtracting Vectors

  6. Combining Vectors

  7. Using the Tip-to-Tail Rule

  8. Clicker Question 1 Question: Which vector shows the sum of A1 + A2 + A3 ?

  9. Multiplication by a Scalar

  10. Coordinate Systems and Vector Components Determining the Components of a Vector 1. The absolute value |Ax| of the x-component Ax is the magnitude of the component vector . 2. The sign of Axis positive if points in the positive x-direction, negative if points in the negative x-direction. 3. The y- and z-components, Ay and Az, are determined similarly. xA x A x A Knight s Terminology: The x-component Ax is a scalar. The component vector is a vector that always points along the x axis. x A The vector is , and it can point in any direction. A

  11. Determining Components

  12. Cartesian and Polar Coordinate Representations

  13. Unit Vectors i = = = = (1,0,0) unit vector in +x-direction = "i-hat" j (0,1,0) unit vector in +x-direction = "j-hat" = = (0,0,1) unit vector in +z-direction = "k-hat" k = + + = + + = ( , , ) A A A A A i A j A k A A A x y k x y z x y z Example: i j = + = (4, 2,5) 4 2 5 B k

  14. Working with Vectors ^ A = 100 i m B = ( 200 Cos 450 i + 200 Cos 450 j ) m = ( 141 i + 141 j ) m ^ ^ ^ ^ C = A + B = (100 i m) + (-141 i + 141 j ) m = (-41 i + 141 j ) m ^ ^ ^ ^ C = [Cx2 + Cy2] = [(-41 m)2 + (141 m)2] = 147 m = Tan-1[Cy/|Cx|] = Tan-1[141/41] = 740 Note: Tan-1 ATan = arc-tangent = the angle whose tangent is

  15. Tilted Axes Cx = C Cos Cy = C Sin

  16. Arbitrary Directions

  17. Perpendicular to a Surface

  18. Chapter 3 Summary (1)

  19. Chapter 3 Summary (2)

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