Understanding Electrostatic Properties of Polyelectrolyte Solutions for DNA Molecules
Double-stranded DNA molecules exhibit repulsion due to their linear charge distribution, which can be mitigated by positively charged counter-ions. The Bjerrum length and Manning structural parameter play crucial roles in defining charge density. Electrostatic repulsion terms and calculations involving univalent salt interactions in water further shed light on the complex nature of DNA behavior in solution.
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DNA coby polyelektrolyt: Manningova teorie kondenzace protiiont F5351 Z klady molekul rn biofyziky Masarykova Univerzita Podzimn semestr 2021 26.11.2021 Prof. Ji Kozelka, Biofyzik ln Laborato , stav fyziky kondenzovan ch l tek, P F MU, Kotl sk 2, kozelka.jiri@gmail.com Manning, G. S. (1978). "The molecular theory of polyelectrolyte solutions with aplications to the electrostatic properties of polynulceotides." Quart. Rev. Biophys. 11: 179-246.
Double-stranded DNA can be considered as a linear long rod composed of segments, each carrying one unit charge. The segments repel each other. The repulsion is diminished if positively charged counter-ions associate with the DNA surface. 1 segment: charge -1e DNA double helix _ _ _ _ _ __ _ _ _ _ _ b = 1.7 The distance b between segments harboring a unit charge (1 qe=1.60x10-19 C) defines the charge density of the polymer. For single-stranded DNA, b = 3.4 For double-stranded DNA, b =1.7
Before we continue, let us learn about two definitions: Bjerrum* length lB: the distance between two elementary charges (qe) at which their repulsion energy is equal to the thermal energy kBT 2 2 ??? =???? ??=???? ??? ???? *Niels Jannicksen Bjerrum (1879-1958), d nsk chemik Manning** structural parameter : the ratio between lBand b, that is, the product of the Bjerrum length (a constant [ ]) and the linear charge density ([ -1]). It is thus a dimensionless parameter proportional to the charge density. =?? ?= 2 ???? ????? ** Gerald S. Manning, professor emeritus, Rutgers University, New Jersey, USA
Univalent salt in water (e.g., NaCl) + + + + + At each segment, a fraction of positive counterions condenses within a volume VP + VP _ DNA double helix _ _ _ _ __ _ _ _ _ _ + The charge of 1 segment is reduced to (-1+ )e Gain in enthalpy H, since repulsion between segments is diminished Loss in entropy S, since order increases Nature will choose such a fraction, that G = H T S is minimal + + + 1 equation 2 unknowns + + G/ = 0 G( , VP ) / = 0
Calculation of the electrostatic repulsion term Gel Phosphate N : 1 Charge: 2 3 ..s np qnet qnet qnet qnet qnet qnet qnet qnet b 2b efekt soli qnet = qe(1- ) i jb r 2 e 2 k q (1- ) i- b = e Each pair contributes: G e D ij j efekt vody Debye-H ckel screening factor if np>> s np np Coulomb rD= Debye screening length proportional to c-1/2 c: concentration of univalent salt All pairs contribute: |i-j| = 1: number of pairs = np-1 |i-j| = 2: number of pairs = np-2 . . |i-j| = s: number of pairs = np-s |i-j| > s: interaction negligible i-jb r 2 e 2 n L k q (1- ) b 1 i-j s p AV e G = e D el np Gij 0 i-j =1
Simplifying the sum over pairwise electrostatic repulsion terms i-jb r 2 e 2 n L k q (1- ) b 1 i-j s p AV e G = e D el i-j=1 i-jb r b r 2b r 3b r 1 i-j 1 2 1 3 s e = e + e + e +... D D D D i-j=1 Looks like a Taylor series . Cvi en 1: odvo te Taylor v rozvoj pro funkci f(x)=ln(1+x) (vy adov no je e en , nikoliv jen v sledek) Taylor v rozvoj : f(x) =
f(x) = 1 x = ( " f ) x = + ( ) ln( 1 ) f x x + 2 1 ( ) 1 2 = ( ' ) f x = ( ' " f ) x + 1 x + 3 1 ( ) x with a=0: 2 3 series converges for x<0 x x = + = + + ( ) ln( 1 ) ln 1 ...... f x x x 2 3 = /D r b : x e with 2 / 3 / b r b r e e D D = / / b r b r ln( 1 ) 0 ...... e e D D 2 3
List of Taylor series of some common functions http://en.wikipedia.org/wiki/Taylor_series
Simplifying the sum over pairwise electrostatic repulsion terms i-jb r 2 e 2 n L k q (1- ) b 1 i-j s p AV e G = e D el Cvi en 2: vypo t te sumu i-j=1 -i-jb r -b r -b r -2b r -3b r -b r s 1 i-j 1 2 1 3 since e e = e + e + e +... 1 = -ln(1-e ) D = D D D D D i-j=1 2 3 4 x 2 x 6 x 24 x e = 1+ x + + + +... -b r b r -ln(1-e ) xe = 1+x for x<<1 = -ln( ) since r b Cvi en 3: zjednodu te (rD>>b) D D D
Simplifying the sum over pairwise electrostatic repulsion terms i-jb r 2 e 2 n L k q (1- ) b 1 i-j s p AV e G = e D el Sum has become a simple logarithmic term! i-j=1 i-jb r b r 2b r 3b r 1 i-j 1 2 1 3 b r s e = e + e + e +...= -ln( ) D D D D i-j=1 D 2 e 2 n L k q (1- ) b b r p AV e G =- ln( ) el D is the dimensionless Manning structural factor proportional to charge density 2 e k q b kT 1 with = e b r b r 2 ln( ) < 0; G 0 G = - RTn (1- ) ln( ) el p el D D
Cvien 4: Vypotte pro dvojroubovicovou DNA (b = 1.7 ) p i 25 C 2 e e k q 1 with = b kT = 4.2 (single-stranded DNA: = 2.1) k = 1.38x10-23J.K-1 ke= 9.0x109Nm2C-2 T = 298 K = 78 qe= 1.60x10-19C
cbulk + + clocal= nP (nPVP)-1= VP-1 + + + A fraction of positive counterions condenses within a volume VP + VP _ DNA double helix _ _ _ _ __ _ _ _ _ _ + Loss in entropy S, since order increases + + + + +
Mixing entropy term dependent on 1 c V = = G RTln( ) RTln( ) local P n n mix P P c c bulk number of moles of couterions that is confined from cbulkto clocal cbulk= c = concentration [mol/L] of univalent salt KNOWN VP [L/mol] = volume to which the counterions/phosphate are confined VpUNKNOWN HOPELESS CALCULATION??? Let s minimize the total free energy with respect to ( G)/ = 0 1 b V = + = + 2 RTn [ ln( ) ln( )] P G G G (1 ) el mix P r c D i.e., loss in entropy when the fraction of counterions associates with each segment
Cvien 5: Vypotte prvn derivaci nsleduj funkce podle x : 1 = ( ) ln ( ) f x + 1 2x 1 = ) 1 1 ( + 1 - 2 - ( ' ) ( ) ( 2 x) 2 f x + 1 2x 2 = + 1 2 x
Minimizing total free energy 1 b V = + = + 2 RTn [ ln( ) ln( )] P G G G (1 ) el mix P r c D ( G) 1 b 1 V = + + Cvi en 6: vypo t te derivaci. Nazna te postup v po tu. RTn [ 2 (1 (-1) ln( ) 1 ln( )] P ) P r c D 1 b V = + + RTn [2 (1 ln( ) 1 ln( )] P ) P r c D 2 e k q 1 -3 10 RT 2(L b = e kT m = r 0 D 2 q ) c AV e Dependence of Gmixon c Dependence of Gelon c From Debye-H ckel Theory of electrolytes
1 b ( G) V = + + = RTn [2 (1 ln( ) 1 ln( )] 0 P ) P r c D 2 e k q 1 -3 10 RT 2(L m = b = e kT r 0 D 2 q ) c AV e 1 2 1 2 2 e 2 AV kT 10 2 e 2 e 6 e k q 2L q c 2k q L ( kT) 10 c b r 1( = = ) ( ) e kT L AV 3 -3 2 -3 D 0 AV 0 2 e 6 e 2k q L c 1 c + = 2 (1 ln[ ] 1 ln( ) 0 AV ) kT) 2 3 3 1 2 ( 10 V 0 P 2 e 6 e 2k q L c c + = (1 ln[ ] 1 ln( ) 0 AV ) kT) 2 3 3 1 ( 10 V 0 P
2 e 6 e 2k q L c c + = (1 ln[ ] 1 ln( ) 0 AV ) kT) 2 3 3 1 ( 10 V 0 P Singular terms containing ln c must vanish! We want to know at the low concentration limit, c 0 ( ) ln c ln c - - (1- ) - 1 = 0 Now we have got a second equation! -1 = 1 - dimensionless charge density of polymer c concentration of univalent electrolyte dielectric coefficient of electrolyte T absolute temperature fraction of counterions condensed VPvolume to which counerions condense k Boltzmann s constant keelectrostatic constant qeelectron charge vacuum permittivity LAVAvogadro s number knowns unknowns
2 e 6 e 2k q L c c + = (1 ln[ ] 1 ln( ) 0 AV ) kT) 2 3 3 1 ( 10 V 0 P Singular terms containing ln c must vanish! We want to know at the low concentration limit, c 0 ( ) ln c ln c - - (1- ) - 1 = 0 DNA in water: 1 Now we have got a second equation! = 1 1 = - - -1 = 4.2 = 0.76 76% of the negative charge of the phosphates is neutralized by condensed counterions! no association of counterions association of counterions
Now we can determine VP, the volume to which the counterions/nucleotide condense in double-stranded DNA c L q 2k ln[ ) (1 3 0 2k [ ln ) (1 ln(c) ) (1 0 2k [ ln ) (1 0 =1 2 e 6 e c + = AV ] 1 ln( ) 0 2 3 1 ( kT) 10 V base of natural logarithms ln(c) ] + P 2 6 e q L e AV + = ln( ) 0 kT) 2 3 3 ( 10 V P 2 e 6 e q L e 3 = AV ] 0 2 3 ( kT) 10 V P =0 2 e 6 e 2k q L e 3 = AV L 1 kT) 2k 2 3 ( 10 V 0 P 2 e ( 6 e kT) q e = AV V P 2 3 3 10 0
2 e ( 6 e kT) 2k q L e = AV V P 2 3 3 10 0 2 e 6 e 2k 2 q L e = = = 4 - 3 AV V . 0 646 L/mole 6.46x10 m / mole P kT) 3 3 ( 10 0 = 6.46x1026LAV-1 3/nucleotide = 1073 3/nucleotide = 8.85x10-12C2N-1m-2 LAV= 6.02x1023mole-1 e = 2.718 k = 1.38x10-23J.K-1 ke= 9.0x109Nm2C-2 qe= 1.60x10-19C DNA in water at 25 C = 4.2 =78 T = 298 K = 0.76
The volume to which the condensed univalent counter-cations are confined, VP Per mole: 646 cm3 Per nucleotide: 1073 3 This corresponds to a layer of ~7 around the DNA double-helix (which corresponds ~to a cylinder with a diameter of 20 ) 7 20 7 Counterion Condensation Theory: Manning, G. S. (1978) Quart. Rev. Biophys. 11: 179-246
Experimental and theoretical results supporting the Counterion Condensation Theory 1. Titration of Carboxymethylcellulose (CMC) with different hydroxides monitored by ultrasonic absorption O O OH OH O O OH OH O OH O OH O O CMC OH OH O O O OH OH O O OH + OH- OH O O O- + H2O O Titration with XOH; X = Na, K, Li, N(CH3)4 . Upon titration, the COOH groups are successively deprotonated, become COO-, and the negative charge density increases. This modifies the structure of the water layer at the surface of the polymer, which can be monitored by measuring the absorption of ultrasound. If there is no association of cations with the polyanion, the structure of the water layer should be independent of the cation.
> 1: great differences between the various hydroxides association between the counterions and the polymer, as predicted by the Manning theory < 1: no difference between the various hydroxides association between the counterions and the polymer no R. Zana et al., J. Chim. Phys, 68, 1258-1266 (1971)
2. Molecular dynamics simulations of a solvated DNA duplex % phosphate charge 7 20 7 [ ] Radial distribution of Na+counterions around a DNA duplex 12 base-pairs long, from a molecular dynamics simulation (Yang et al., J. Am. Chem. Soc. 1997, 119, 59-69). The calculation predicts 82% of the phosphate charge to be neutralized, with cations moving within a radius of 15 from the helix axis. Manning theory predicts 76% of cations within 17 from the helix axis.
Remember: -1 = 1- In a diluted solution of counterions, is concentration-independent! = fraction of monovalent cations predicted by Counterion Condensation Theory to condense on each unit charge of the poly-anion If then a fraction of 1- -1counterions condense at each unit charge If , there is no counterion condensation. duplex DNA in H2O at 298 K: = 4.2 single-stranded DNA: = 2.1
(ax)*lna http://matematika-online-a.kvalitne.cz/derivace-funkce.htm