Second-Order RLC Circuits in Electronics

 RLC circuits
Unit-2(ECE-S202)
(Atul Kr. Agnihotri )
 Second-Order Circuits
 RLC circuits
A Bit on Second-Order Circuits
A second-order circuit consists of resistors and the equivalent of two
energy storage elements (Ls, Cs).  A second-order circuit is characterized
by a second-order differential equation (contains second-derivatives of time) 
Example:  A circuit containing R, L and C in series with a voltage source;
     a circuit with R, L and C in parallel.
Initial and final values of v, i, dv/dt, and di/dt
Example:  The switch in this circuit has been closed for a long time.  It opens
  at t = 0.  Find: i(0+), v(0+), 
d
i(0+)/
dt
, 
d
v(0+)/
dt
, i(infinite time), v(infinite time)
a.
Values for t < 0
b.
Values for t = 0
+
c.
Values for t = infinity
a.
Values for t < 0
b.  Values for t = 0+
c.  Values for t = infinity
A 2nd Order RLC Circuit
Application: Filters
A bandpass filter such as IF amplifier for the
AM radio.
A lowpass filter with a sharper cutoff than can
be obtained with an RC circuit.
The Differential Equation
KVL around the loop:
v
r
(t) + v
c
(t) + v
l
(t) = v
s
(t)
i
 
(t)
The Differential Equation
The voltage and current in a second order circuit is the
solution to a differential equation of the following
form:
x
p
(t)
 is the particular solution (forced response) and
x
c
(t)
 is the complementary solution (natural response).
(the forcing function –
the driving voltage or
current source)
The Particular Solution
The particular solution 
x
p
(t)
 is usually a
weighted sum of 
f(t)
 and its first and second
derivatives.
If 
f(t)
 is constant, then 
x
p
(t)
 is constant.
If 
f(t)
 is sinusoidal, then 
x
p
(t)
 is sinusoidal
   (with the same frequency as the source, for a
circuit of only linear elements)
The Complementary Solution
The complementary solution has the following form:
K
 is a constant determined by initial conditions.
s
 is a constant determined by the coefficients of the
differential equation.
Characteristic Equation
To find the complementary solution, we need
to solve the characteristic equation:
The characteristic equation has two roots-call
them 
s
1
 and 
s
2
.
 
Overdamped, critically damped and underdamped response of
source-free transiently excited 2nd-order RLC circuit
Assume circuit is excited by energy stored in C or L
of series RLC circuit.
Assume i(t) = K
1
e
s1t
 + K
2
e
s2t
 where (with slightly
  different notation)
 = R/2L is called the damping factor and
                         is the undamped natural frequency
If 
 > 
0
 
 overdamped case a
If 
 = 
 
 critically damped case b
If 
< 
 
 underdamped case c
 
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Explore second-order RLC circuits in electronics, characterized by second-order differential equations and involving resistors, inductors, capacitors, and voltage sources. Learn about initial and final values of voltage and current, applications in filters, and the differential equations governing these circuits.

  • RLC Circuits
  • Electronics
  • Second-Order
  • Filters
  • Differential Equations

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  1. RLC circuits Unit-2(ECE-S202) (Atul Kr. Agnihotri ) Second-Order Circuits RLC circuits

  2. A Bit on Second-Order Circuits A second-order circuit consists of resistors and the equivalent of two energy storage elements (Ls, Cs). A second-order circuit is characterized by a second-order differential equation (contains second-derivatives of time) Example: A circuit containing R, L and C in series with a voltage source; a circuit with R, L and C in parallel.

  3. Initial and final values of v, i, dv/dt, and di/dt Example: The switch in this circuit has been closed for a long time. It opens at t = 0. Find: i(0+), v(0+), di(0+)/dt, dv(0+)/dt, i(infinite time), v(infinite time) a. Values for t < 0 b. Values for t = 0+ c. Values for t = infinity

  4. a. Values for t < 0

  5. b. Values for t = 0+

  6. c. Values for t = infinity

  7. A 2nd Order RLC Circuit i(t) R + vs(t) C - L Application: Filters A bandpass filter such as IF amplifier for the AM radio. A lowpass filter with a sharper cutoff than can be obtained with an RC circuit.

  8. The Differential Equation i(t) vr(t) + - R + + vc(t) vs(t) C - - vl(t) - + KVL around the loop: L vr(t) + vc(t) + vl(t) = vs(t) 1 ( ) ( ) Ri t i x dx C ( ) 1 ( ) i t L dt LC t ( ) dt di t + + = ( ) L v t s 2 ( ) ( ) 1 L dv t dt R di t d i t dt + + = s 2

  9. The Differential Equation The voltage and current in a second order circuit is the solution to a differential equation of the following form: 2 ( ) ( ) dt d x t dt dx t (the forcing function + + = 2 0 2 ( ) x t ( ) f t the driving voltage or 2 current source) = + ( ) x t ( ) ( ) x t x t p c xp(t) is the particular solution (forced response) and xc(t) is the complementary solution (natural response).

  10. The Particular Solution The particular solution xp(t) is usually a weighted sum of f(t) and its first and second derivatives. If f(t) is constant, then xp(t) is constant. If f(t) is sinusoidal, then xp(t) is sinusoidal (with the same frequency as the source, for a circuit of only linear elements)

  11. The Complementary Solution The complementary solution has the following form: ( ) = st cx t Ke K is a constant determined by initial conditions. s is a constant determined by the coefficients of the differential equation. 2 st st d Ke dt dKe dt + + = 2 0 st 2 0 Ke 2 + + = 2 2 0 st st st 2 0 s Ke sKe Ke + + = 2 2 0 2 0 s s

  12. Characteristic Equation To find the complementary solution, we need to solve the characteristic equation: 2 0 2 s s = + + = 2 0 0 0 The characteristic equation has two roots-call them s1 and s2. ( ) K e = + s t s t c x t K e 1 2 1 2 = + 2 1 s 1 0 0 = 2 1 s 2 0 0

  13. Overdamped, critically damped and underdamped response of source-free transiently excited 2nd-order RLC circuit Assume circuit is excited by energy stored in C or L of series RLC circuit. Assume i(t) = K1es1t + K2es2t where (with slightly different notation) s 1 + = 2 2 0 2 = 2 s where 2 0 = / 2 R L = 1 / LC = R/2L is called the damping factor and is the undamped natural frequency LC / 1 0= If > 0 overdamped case a If = critically damped case b If < underdamped case c

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