Momentum and Forces in Physics

A2 Physics Unit 4
1 Forces & Momentum
Mr D Powell
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Momentum
A rocket of mass 5 kg is travelling
horizontally with a speed of 200 ms
-1
 when it
explodes into two parts.  One part of mass 3
kg continues in the original direction with a
speed of 100 ms
-1
.  The other part also
continues in this same direction.  Calculate
its speed.
m = 5 kg
u = 200 ms
-1
m
1
 = 3 kg
m
2
 = m – m
1
 = 5 – 3 = 2 kg
v
1
 = 100 ms
-1
v
2
 = v
2
momentum before the explosion = momentum after the explosion
 
mu = m
1
v
1
 + m
2
v
2
(5 x 200) = (3 x 100) + (2 x v
2
)
1000 = 300 + 2v
2
1000 – 300 = 2v
2
700 = 2v
2
v
2
 = 700/2
v
2
 = 350 ms
-1
undefined
 
D
(mv-mu )/t so kgms
-2
W = mg or F=ma
A
Cons of Momentum
0 = m
1
v
1
 – m
2
v
2
undefined
3
A
If 100% elastic
momentum is passed
through to T
2
 so T
1
must be at rest.
 
As same mass the
velocity is unaltered
undefined
A
Ft     = mv-mu
(mv-mu) /F  = t
mv/F  = t
584.6 x 10
-6
undefined
B
p  = momentum = mv
 = m/V
V = m
p = (
V) * v
v = 2 x 10
-4
m
3
 / 7.2 x 10
-4
ms
-1
 = 0.277ms
-1
1000kgm
-3
 x 2.0 x 10
-4
 m
3
 x   0.277ms
-1  
=  0.05555 kgms
-1 
=  0.056 kgms
-1
undefined
 
B
Ft = mv-mu
F = (mv-mu)/t
F = ∆mv/t
undefined
C
Area under graph...ft
5kN x 40/2 = 100kNs
-1
Then mv = momentum.
mv/m = 50ms
-1
undefined
D
mv-mu
v=-u
This becomes...
mv-(m-u)
2mv
undefined
C
Ft=mv-mu
undefined
B
v = 2x10
-4
 m
3
s
-1
  / 7.2x10
-4
m
2
  = 0.2778ms
-1
mass per second = 1000kgm
-3
 x 2x10
-4
 m
3
s
-1
 = 0.2kgs
-1 
mv = 5.6 x 10
-2
Momentum = mv
 = m/V
V = m
V
v = mv
undefined
D
Inelastic means that you lose some KE to
thermal/sound in the smash
But you always conserve mass and total energy and
momentum in any collision
undefined
 
D
B
∆mu/t = F
F = ma
∆p= mv –(-mu) = 2mv
v=u  as elastic!
undefined
 
C
Area under graph is Ft = mv-mu
(5s x 10N )/ 2 = 25Ns
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Concept of momentum and forces in physics through examples and calculations. Understand the principles of momentum conservation and how it relates to collisions and explosions. Dive into the dynamics of objects in motion and the interplay of forces that govern their behavior. Gain insights into the practical applications of these fundamental physical principles in real-world scenarios.

  • Physics
  • Momentum
  • Forces
  • Conservation
  • Collisions

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  1. A2 Physics Unit 4 1 Forces & Momentum Mr D Powell

  2. Momentum m = 5 kg u = 200 ms-1 m1 = 3 kg m2 = m m1 = 5 3 = 2 kg v1 = 100 ms-1 v2 = v2 A rocket of mass 5 kg is travelling horizontally with a speed of 200 ms-1 when it explodes into two parts. One part of mass 3 kg continues in the original direction with a speed of 100 ms-1. The other part also continues in this same direction. Calculate its speed. momentum before the explosion = momentum after the explosion mu = m1v1 + m2v2 (5 x 200) = (3 x 100) + (2 x v2) 1000 = 300 + 2v2 1000 300 = 2v2 700 = 2v2 v2 = 700/2 v2 = 350 ms-1 Animated Science 2016

  3. D (mv-mu )/t so kgms-2 W = mg or F=ma Cons of Momentum 0 = m1v1 m2v2 A Animated Science 2015

  4. 3 A If 100% elastic momentum is passed through to T2 so T1 must be at rest. As same mass the velocity is unaltered Animated Science 2015

  5. Ft = mv-mu (mv-mu) /F = t mv/F = t 584.6 x 10-6 A

  6. p = momentum = mv = m/V V = m p = ( V) * v v = 2 x 10-4m3 / 7.2 x 10-4ms-1 = 0.277ms-1 1000kgm-3 x 2.0 x 10-4 m3 x 0.277ms-1 = 0.05555 kgms-1 = 0.056 kgms-1 B

  7. B Ft = mv-mu F = (mv-mu)/t F = mv/t Animated Science 2016

  8. C Area under graph...ft 5kN x 40/2 = 100kNs-1 Then mv = momentum. mv/m = 50ms-1 Animated Science 2016

  9. D mv-mu v=-u This becomes... mv-(m-u) 2mv Animated Science 2016

  10. C Ft=mv-mu Animated Science 2016

  11. B v = 2x10-4 m3s-1 / 7.2x10-4m2 = 0.2778ms-1 mass per second = 1000kgm-3 x 2x10-4 m3s-1 = 0.2kgs-1 mv = 5.6 x 10-2 Momentum = mv = m/V V = m Vv = mv Animated Science 2016

  12. D Inelastic means that you lose some KE to thermal/sound in the smash But you always conserve mass and total energy and momentum in any collision Animated Science 2016

  13. mu/t = F F = ma D p= mv (-mu) = 2mv v=u as elastic! B Animated Science 2016

  14. C Area under graph is Ft = mv-mu (5s x 10N )/ 2 = 25Ns Animated Science 2016

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