Mathematical Analysis of Algorithms in CMPE371 - Fall 2023-2024

Explore the mathematical analysis of algorithms in CMPE371 for Fall 2023-2024, focusing on non-recursive and recursive algorithms. Learn how to analyze non-recursive algorithms by deciding on input size parameters, identifying basic operations, and simplifying summations. Dive into recursive algorithms, where you divide, solve, and conquer sub-problems through recursion. Calculate algorithmic complexity and understand the steps for analyzing recursive algorithms based on input size and conditional operations.

• CMPE371
• Algorithms
• Mathematical Analysis
• Fall 2023
• Recursive Algorithms

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1. CMPE371 Analysis of Algorithms FALL 2023-2024 Lecture 4 Part I

2. Mathematical Analysis of Non-recursive Algorithms Remember that steps in mathematical analysis of non-recursive algorithms are: Decide on parameter n indicating input size Identify algorithm s basic operation Determine worst anf best case for input of size n Set up summation for C(n) reflecting algorithm s loop structure Simplify summation using standard formulas. 2

3. Divide and Conquer: Recursive Algorithms Main Idea: 1. Divide the given problem to sub-problems 2. Solve the sub-problems independent of each other. 3. Conquer the solutions By recursion! 3

4. Simple Example SimpleExample(N) IF N=0 THEN RETURN ELSE 1 FOR i 1 TO N DO PRINT( x ) SimpleExample(N-1) N+1 N T(N-1) T(N) = O(1) if N=0 = (N+1)+N+T(N-1) = T(N-1)+ (N), Otherwise

5. Calculating the algorithmic complexity of a recursive algorithm

7. Mathematical Analysis of Recursive Algorithms Steps in mathematical analysis of recursive algorithms Decide on parameter n indicating input size Identify algorithm s basic operation Determine worst and best case for input of size n; depending on the conditional operations in algorithm. Set up a recurrence relation and initial condition(s) Solve the recurrence to obtain a closed form or estimate the order of growth of the solution. 7

12. How many moves does it take? Did you know you should be able to complete the puzzle in (2n-1) moves where n is the number of disks. For 3 disks 2n-1= (23 1) = (8-1) =7 moves

14. Merge Sort Approach To sort an array A[p . . r]: Divide Divide the n-element sequence to be sorted into two subsequences of n/2 elements each Conquer Sort the subsequences recursively using merge sort When the size of the sequences is 1 there is nothing more to do Merge Merge the two sorted subsequences

15. Merge Sort r p q 1 5 2 2 3 4 4 7 5 1 6 3 7 2 8 6 Alg.: MERGE-SORT(A, p, r) if p < r Check for base case then q (p + r)/2 Divide MERGE-SORT(A, p, q) Conquer MERGE-SORT(A, q + 1, r) Conquer MERGE(A, p, q, r) Combine Initial call: MERGE-SORT(A, 1, n)

16. Example n Power of 2 1 5 2 2 3 4 4 7 5 1 6 3 7 2 8 6 Divide q = 4 1 5 2 2 3 4 4 7 5 6 7 8 1 3 2 6 1 5 2 2 3 4 4 7 5 6 7 8 1 3 2 6 5 1 5 2 2 3 4 4 7 6 7 8 1 3 2 6

17. Example n Power of 2 1 1 2 2 3 2 4 3 5 4 6 5 7 6 8 7 Conquer and Merge 1 2 2 4 3 5 4 7 5 6 7 8 1 2 3 6 1 2 2 5 3 4 4 7 5 6 7 8 1 3 2 6 5 1 5 2 2 3 4 4 7 6 7 8 1 3 2 6

18. Example n Not a Power of 2 1 2 3 4 5 6 7 8 9 10 11 4 7 2 6 1 4 7 3 5 2 6 q = 6 Divide 1 2 3 4 5 6 7 8 9 10 11 4 7 2 6 1 4 7 3 5 2 6 q = 3 q = 9 1 2 3 4 5 6 7 8 9 10 11 4 7 2 6 1 4 7 3 5 2 6 1 2 3 4 5 6 7 8 9 10 11 4 7 2 6 1 4 7 3 5 2 6 1 2 4 5 7 8 4 7 6 1 7 3

19. Example n Not a Power of 2 1 2 3 4 5 6 7 8 9 10 11 Conquer and Merge 1 2 2 3 4 4 5 6 6 7 7 1 2 3 4 5 6 7 8 9 10 11 1 2 4 4 6 7 2 3 5 6 7 1 2 3 4 5 6 7 8 9 10 11 2 4 7 1 4 6 3 5 7 2 6 1 2 3 4 5 6 7 8 9 10 11 4 7 2 1 6 4 3 7 5 2 6 1 2 4 5 7 8 4 7 6 1 7 3

20. Merging r p q 1 2 2 4 3 5 4 7 5 1 6 2 7 3 8 6 Input: Array A and indices p, q, r such that q < r Subarrays A[p . . q] and A[q + 1 . . r] are sorted Output: One single sorted subarray A[p . . r] p

21. r p q Merging 1 2 2 4 3 5 4 7 5 1 6 2 7 3 8 6 Idea for merging: Two piles of sorted cards Choose the smaller of the two top cards Remove it and place it in the output pile Repeat the process until one pile is empty Take the remaining input pile and place it face-down onto the output pile A1 A[p, q] A[p, r] A2 A[q+1, r]

22. Example: MERGE(A, 9, 12, 16) p p q q r r

23. Example: MERGE(A, 9, 12, 16)

24. Example (cont.)

25. Example (cont.)

26. Example (cont.) Done!

27. Merge - Pseudocode Alg.: MERGE(A, p, q, r) 1. Compute n1and n2 2. Copy the first n1elements into L[1 . . n1+ 1] and the next n2elements into R[1 . . n2+ 1] 3. L[n1+ 1] ; 4. i 1; j 1 5. for k p to r 6. do if L[ i ] R[ j ] 7. then A[k] L[ i ] 8. i i + 1 9. else A[k] R[ j ] 10. j j + 1 r p q 1 2 2 4 3 5 4 7 5 1 6 2 7 3 8 6 n2 n1 R[n2+ 1] p q 2 4 5 7 L q + 1 r 1 2 3 6 R

28. Running Time of Merge (assume last for loop) Initialization (copying into temporary arrays): (n1+ n2) = (n) Adding the elements to the final array: - n iterations, each taking constant time (n) Total time for Merge: (n)

29. Analyzing Divide-and Conquer Algorithms The recurrence is based on the three steps of the paradigm: T(n) running time on a problem of size n Divide the problem into a subproblems, each of size n/b: takes D(n) Conquer (solve) the subproblems aT(n/b) Combine the solutions C(n) (1) T(n) = aT(n/b) + D(n) + C(n) otherwise if n c

30. Recurrence Examples = = 0 0 n 0 0 n = ( ) T n = ( ) T n + ( ) 1 0 n T n n + ( ) 1 0 c T n n = = 1 c n 1 c n = ( ) T n = ( ) T n n n + + 1 aT cn n 2 1 T c n b 2

31. Methods for Solving Recurrences Substitution method Iteration method Recursion tree method Master method